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vazorg [7]
3 years ago
14

Convert 2.0 micrometer to centimeters and to inches

Chemistry
1 answer:
Dima020 [189]3 years ago
7 0

Answer:

2x10⁻⁴cm and 7.9x10⁻⁵ inches

Explanation:

Micrometer, μm, is an unit of length. Could be related with another units of lenght as, for example:

1.0μm = 1x10⁻⁴cm

1.0μm = 3.93701x10⁻⁵ inches

That means, 2.0μm are:

2.0μm * (1x10⁻⁴cm / 1μm) = 2x10⁻⁴cm

And:

2.0μm * (3.93701x10⁻⁵ inches / 1μm) = 7.9x10⁻⁵ inches

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A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e
german

Answer: 8.57 ml of KOH is required to reach the equivalence point.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?

Putting values in above equation, we get:

1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL

Thus 8.57 ml of KOH is required to reach the equivalence point.

8 0
4 years ago
What is the molar mass of Disodium sulfide nonahydrate
Scilla [17]

Answer:

240 g/mol

Explanation:

We'll begin by writing the chemical formula of Disodium sulfide nonahydrate. This is illustrated below:

The molecular formula of disodium sulfide nonahydrate is Na₂S.9H₂O

Finally, we shall determine the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O. This can be obtained by adding the individual molar mass of the element present in the compound as illustrated below:

Molar mass of Na₂S.9H₂O = (23×2) + 32 + 9[(2×1) + 16]

= 46 + 32 + 9[2 + 16]

= 46 + 32 + 9[18]

= 46 + 32 + 162

= 240 g/mol

Thus, the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O is 240 g/mol

7 0
3 years ago
What type of plants contain tubes that help transport water and nutrients into their other parts?
cricket20 [7]

Answer:

A

Explanation:

6 0
3 years ago
Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18(l) + 25 O2(
scoray [572]
2C₈H₁₈ + 25O₂ = 16CO₂ + 18H₂O

n(C₈H₁₈)=4 mol
n(O₂)=4 mol

C₈H₁₈:O₂=2:25 ⇒ 4:50  oxygen is the limiting reagent

n(CO₂)=16n(O₂)/25

n(CO₂)=16*4/25=2.56 mol
6 0
3 years ago
Read 2 more answers
If 75 gm's of codeine phosphate is dissolved in 1.5 liters of sterile water, what is the resultant percentage strength of the so
Slav-nsk [51]

Answer:

w/v% = gm per 100 ml

75gm X gm 7500

------- = ------ == --------

1500ml 100ml 1500X

X=5%

5 0
3 years ago
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