Answer:
2.61 L
Explanation:
p1v1 = p2v2
p1v1 / p2 = v2
98 * 2 / 75 = v2 = 2.61 L
Answer: 0.0345 sec
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![Rate=k[H_3PO_4]^2](https://tex.z-dn.net/?f=Rate%3Dk%5BH_3PO_4%5D%5E2)
k= rate constant = 
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
for completion of 20 % of reaction
The time taken for the concentration of 
to decrease to 20% to its natural value is 0.0345 sec
The answer is 1,085
Since every 10 degrees in tempature t would add up 25 so mutiply 25x5=125+960=1,085
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Answer:
25.0 mL
Explanation:
1. Gather the information in one place.
MM: 98.00 74.09
2H3PO4 + 3Ca(OH)2 → Ca3(PO4)2 + 6H2O
m/g: 8.85 15.76
V/mL: 350.0 550
2. Moles of H3PO4
n = 8.85 g × (1 mol/98.00 g) = 0.09031 mol H3PO4
3. Moles of Ca(OH)2
n = 15.76 g × (1 mol/74.09 g) = 0.2126 mol Ca(OH)2
4. Moles of Ca(OH)2 in 25.0 mL Solution
n = 0.2126 mol × (25.0 mL/550 mL) = 0.009 663 mol Ca(OH)2
5. Moles of H3PO4 needed
From the balanced equation, the molar ratio is 2 mol H3PO4: 3 mol Ca(OH)2
n = 0.009 663 mol Ca(OH)2 × (2 mol H3PO4/3 mol Ca(OH)2)
= 0.006 442 mol H3PO4
6. Volume of H3PO4
V = 0.006 442 mol ×( 350.0 mL/0.09031 mol) = 25.0 mL H3PO4
It will take 25.0 mL of the H3PO4 solution to neutralize 25.0 mL of the Ca(OH)2 solution.
