Question

How many numbers of atoms there are in 1.14 mol of (SO3)

Answer 1

called the Avogadro number 

N(A)= 6.02 x 10^23 mol^-1 

1 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules. 

thus, 1.14moles will contain; 

= 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23

atoms O/1mol O] 

= 2.05884 x 10^24 oxygen atoms 

= 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23

atoms O/1mol O] 

= 6.8628 x 10^23 sulfur atoms 

hope this helps:-)