Explanation:
It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is and final temperature is .
(a) We know that for a monoatomic gas, value of is \frac{5}{3}[/tex].
And, in case of adiabatic process,
= constant
also, PV = nRT
So, here = 350 K, , and
Hence,
= 267 K
Also, = 4.0 atm, , and
= 2.04 atm
Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.
(b) For diatomic gas, value of is \frac{7}{5}[/tex].
As, = constant
also, PV = nRT
= 350 K, , and
= 289 K
And, = 4.0 atm, , and
= 2.27 atm
Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.
Because the molecules that move freely begin to compact closer together, with less heat, means less molecular activity.
Answer:
Δt ≈ 2.9137 ≈ 3 seconds per kilometer
Explanation:
The speed of light is approximately 300000 km /s, while the speed fo the sound in the air is 0.3432 km/s.
The light takes therefore this time to travel one kilometer
On the other hand the sound takes this time to travel one kilometer
t = 2.9137 s
Then the delay time is 2.9137 -
Δt ≈ 2.9137 ≈ 3 s
W<span>ater particles affected by the movement of a wave because t</span>he wind pushes the water particles down to deeper depths.
Answer:
2.15 m/s²
Explanation:
We'll begin by calculating the force of attraction between two charges. This can be obtained as follow:
Charge of 1st object (q₁) = +11.5 μC = +11.5×10¯⁶ C
Charge of 2nd object (q₂) = –7.55 μC = –7.55×10¯⁶ C
Electrical constant (K) = 9×10⁹ Nm²/C²
Distance apart (r) = 0.925 m
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 11.5×10¯⁶ × 7.55×10¯⁶/ 0.925²
F = 0.781425 / 0.855625
F = 0.91 N
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass of object (m) = 0.423 Kg
Force (F) = 0.91 N
Acceleration (a) =?
F = ma
0.91 = 0.423 × a
Divide both side by 0.423
a = 0.91 / 0.423
a = 2.15 m/s²
Thus, the magnitude of the object's acceleration is 2.15 m/s²