The formula for Fahrenheit and Celsius conversion is
T(°F)<span> = </span>T(°C)<span> × 1.8 + 32
where T is temperature in F or C ( Fahrenheit or Celsius whatever is the case)
</span>This means that keeping this FORMULA in mind we can add different values to it and accordingly convert values from one to another.
Some examples of fahrenheit conversions to Celsius are :
32°F = 0°C using F = (0 x 1.8) + 32
Answer:
The centripetal acceleration is ![a = 11.97 \ m/s^2](https://tex.z-dn.net/?f=a%20%3D%2011.97%20%5C%20m%2Fs%5E2)
Explanation:
From the question we are told that
The radius is ![r = 0.58 \ km = 0.58 * 1000 = 580 \ m](https://tex.z-dn.net/?f=r%20%3D%20%200.58%20%5C%20km%20%3D%20%200.58%20%2A%201000%20%20%3D%20%20580%20%5C%20m)
The speed is ![v = 300\ km /hr = \frac{300 *1000}{1 * 3600 } = 83.33 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20300%5C%20km%20%2Fhr%20%3D%20%20%5Cfrac%7B300%20%2A1000%7D%7B1%20%2A%203600%20%7D%20%20%3D%20%2083.33%20%5C%20m%2Fs)
The centripetal acceleration of the pilot is mathematically represented as
![a = \frac{v^2 }{r}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bv%5E2%20%7D%7Br%7D)
substituting values
![a = \frac{(83.33)^2 }{580}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B%2883.33%29%5E2%20%7D%7B580%7D)
![a = 11.97 \ m/s^2](https://tex.z-dn.net/?f=a%20%3D%2011.97%20%5C%20m%2Fs%5E2)
Answer:
-you have to make yourse;f as light as possible so toss your bag, jacket, and shoes.
-Try to take a few steps backwards.
-Keep your arms up and out of the quicksand.
-Try to reach for a branch or person's hand to pull yourself out.
-Take deep breaths.
-Move slowly and deliberately.
Answer:
6.5 seconds.
Explanation:
Given: h=-16t²+679
When the object reaches the ground, h=0.
∴ 0=-16t²+679
collecting like terms,
⇒ 16t²=679
Dividing both side of the equation by the coefficient of t² i.e 16
⇒ 16t²/16 = 679/16
⇒ t² = 42.25
taking the square root of both side of the equation.
⇒ √t² =√42.25
⇒ t = 6.5 seconds.