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3 years ago

ElectAltEngOnl.19-20.SEC - Theodore Neitzel

Physics

1 answer:

kotykmax [81]3 years ago

4 0

Answer:

Option C is correct.

The resistance of the TV = 68.6 ohms.

Explanation:

According to Ohm's law, the voltage across a device is equal to the product of the current through the device and the resistance across the device.

Since electrical appliances are setup in parallel connection, the voltage across the TV and the PlayStation is the same and is 120 V.

V = IR (From Ohm's law)

V = voltage across the TV = 120 V

I = current flowing through the TV = 1.75 A

R = Resistance of the TV = ?

120 = 1.75 × R

R = (120/1.75) = 68.57 ohms = 68.6 ohms.

Hope this Helps!!!

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4 years ago

The magnitude of a force vector is 89.6 newtons (N). The x component of this vector is directed along the +x axis and has a magn

insens350 [35]

Answer:

(a) θ = 33.86°

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$A_x=Acos\theta$ (1)

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θ: angle between vector A and the x axis

You solve the equation (1) for θ, by using the inverse of cosine function:

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(b) The y component of the vector is given by:

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the y comonent of the vecor is Ay = 49.92 N

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3 years ago

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3 years ago

Read 2 more answers

The force of attraction between a -130.0 C and +180.0 C charge is 8.00 N. What is the separation between these two charges in me

kondaur [170]

Answer with Explanation:

The force of attraction between 2 charges of magnitude $q_1,q_2$ separated by a distance 'r' is given by

$F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}$

where

$\epsilon _o$ is a constant known as permitivity of free space

$k=9\times 10^{9}Nm^2/C^2$

Applying the given values in the above relation we get

$8=9\times 10^{9}\times \frac{130\times 180}{r^{2}}\\\\r^{2}=\frac{9\times 10^{9}\times 130\times 180}{8}\\\\r^{2}=26325\times 10^{9}\\\\\therefore r=\sqrt{26325\times 10^{9}}=5.131\times 10^{6}meters$