Question

Two 0.20-kg balls, moving at 4 m/s east, strike a wall. Ball A bounces backwards at the same speed. Ball B stops. Which statement correctly describes the change in momentum of the two balls?
a. |ΔpBl<|ΔPA|
b. |ΔpBl=|ΔPA|
c. |ΔpB|>|ΔPA|
d. ΔpB > ΔPA

Answer 1

Answer:

Option A

Explanation:

From the question we are told that:

Mass $m=0.20kg$

Velocity $v=4m/s$

Generally the equation for momentum for Ball A is mathematically given by

Initial Momentum

 $M_{a1}=mV$

 $M_{a1}=0.2*4$

 $M_{a1}=0.8$

Final Momentum

 $M_{a2}=-0.8kgm/s$

Therefore

 $\triangle M_a=-1.6kgm/s$

Generally the equation for momentum for Ball B is mathematically given by

Initial Momentum

 $M_{b1}=mV$

 $M_{b1}=0.2*4$

 $M_{b1}=0.8$

Final Momentum

 $M_{b2}=-0 kgm/s$

Therefore

 $|\triangle M_a|>|\triangle Mb|$

Option A