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2 years ago

15

What is one way in which radioactive decay is used to benefit society?

2 answers:

snow_lady [41]2 years ago

7 0

<span>They are used to measure and map effluent and pollution discharges from factories and sewerage plants, and the movement of sand around harbours, rivers and bays. Radioactive materials used for such purposes have short half-lives and decay to background levels within days.</span>

Fudgin [204]2 years ago

4 0

Answer:

Sample Response: Radioisotopes are used in medicine as tracers to detect and diagnose medical problems. Radioisotopes are also used in radiation therapy to treat cancer.

On Edge

Explanation:

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A 1425 kg truck driving at 13.0 m/s collides elastically with a stationary 1175 kg car. If the car is traveling 14.25 m/s just a

TEA [102]

Answer:

1.25 m/s

Explanation:

m1v1+m2v2=m1v1f+m2v2f

(1425*13)+(1175*0)=(1425*v1f)+(1175*14.25)

18525+0=1425(v1f)+16743.75

1781.25=1425(v1f)

v1f=1.25 m/s

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2 years ago

A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the sc

Fantom [35]

Answer:

1. 7.5 m

2. towards west side

explanation:

I hope it will help you

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2 years ago

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

Nostrana [21]

Answer:

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

$E_1 = E_2$

Let the position where net field is zero will lie at distance "r" from q1

$\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}$

now we will have

$\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}$

now square root both sides

$\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}$

now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

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2 years ago

How can velocity change even if speed stays the same?

VARVARA [1.3K]

Answer:

the change of direction it's going

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3 years ago

A car engine applies a force of 65,000 N, how much work is done by the engine as it pushed a car a distance of 75 m?

kupik [55]

Answer:

$workdone = force \times distance \\ = 65000 \times 75 \\ = 4,875,000 \: J$

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2 years ago