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lions [1.4K]
3 years ago
5

A ball is dropped from the roof of a building. Points A, B, C, and D in the diagram below represent positions of the ball as it

falls. At which position will the ball have the greatest kinetic energy?

Physics
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

C. C

Explanation:

The ball will have its greatest kinetic energy just before it touches the ground which is at point C.

Kinetic energy of a body is the energy due to the motion of the body. As a body moves and its speed increases as a result of acceleration, then the kinetic energy will increase more.

As the body starts from rest, at point A, through B and C, the velocity increases drastically due the pull of the earth.

So, point C will show the greatest velocity and hence the most kinetic energy by the body.

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JulsSmile [24]
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just add with a calculator
6 0
3 years ago
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Two adjacent natural frequencies of an organ pipe are found to be 550. Hz and 650. Hz. (a) Calculate the fundamental fre- quency
liubo4ka [24]

Answer:

a) 100Hz

b) opened at both ends

c) 1.72m

Explanation:

Let fun be the nth Harmonic frequency organ. If pipe is opened at both ends.

L= length of pipe

Fyn =(n/x)

550hz= (n/2L)v 1

650hz=(n+1/2L)×v 2

Comparing 1 and 2

650hz= nv/2L + v/2L

550= 343/2L

L= 550×2/343 = 1.7m

c) fundamental frequency

Fo= nv/2L = 343/(2×1.7) = 100Hz

8 0
3 years ago
Suppose that the radius of the circular path is r when the speed of the rocket is v and the acceleration of the rocket has magni
SCORPION-xisa [38]

Answer:

A3

Explanation:

4 0
3 years ago
single goose sounds a loud warning when an intruder enters the farmyard. Some distance from the goose, you measure the sound lev
Goryan [66]

Answer:

The sound level of the 26 geese is  Z_{26}= 96.15 dB

Explanation:

From the question we are told that

    The  sound level is Z_1 =  81.0 \ dB

     The number of geese is N = 26

Generally the intensity level of sound is mathematically represented as

        The intensity of sound level in dB  for one  goose is mathematically represented as

                       Z_1 = 10 log [\frac{I}{I_O} ]

Where I_o is the  threshold level of intensity with value  I_o = 1*10^{-12} \  W/m^2

            I is the intensity for one goose in W/m^2

For 26 geese the intensity would be  

          I_{26} = 26 * I

   Then  the intensity of 26 geese in dB is  

              Z_{26} = 10 log[\frac{26 I }{I_o} ]

               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

               Z_{26} = 10 log (\ \ 26  \ \ ) *   (\ \  10 log [\frac{ I }{I_o} ]\ \ )

 From the law of logarithm we have that

              Z_{26} = 10 log 26 +  10 log [\frac{I}{I_0} ]

                    = 14.15 + 82

                    Z_{26}= 96.15 dB

               

               

           

4 0
3 years ago
A displacement vector 5 units long makes an angle of 67° with the x-axis. What is the horizontal component of displacement?
Harman [31]

Yo sup??

magnitude of original vector is 5 units.

angle made with x axis is 67°

horizontal component=5*cos67°

=5*0.4

=2 units (approx)

Therefore the correct answer is option B

Hope this helps

7 0
3 years ago
Read 2 more answers
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