This is a conversion problem. 760 Torr is equal to 1 atmosphere. so we can can solve now. 5,550torr*(1atmosphere/760torr)=7.3atmospheres. since the two torrs cancel out with cross multiplication we are left in atmosphere units.
the answer should be 20 seconds
Answer:
783 grams
Explanation:
Here mass is given in kg
Some of the prefixes of the SI units are
1 gram = 10⁻³ kilogram
1 milligram = 10⁻⁶ kilogram
1 microgram = 10⁻⁹ kilogram
1 nanogram = 10⁻¹² kilogram
The number is 0.783
Here, the only solution where the number of significant figures is three is gram. If any other prefix is chosen then the significant figures will increase
So, 0.783 kg = 783 grams
Referring to Compton scattering
Δλ = h/m₀c (I- cos Ф)
λ' =λ = (0,0242×10⁻¹⁰) (1- cos 60°)
λ= λ' -(0.0242 × 10⁻¹⁰) (1- cos 60°)
7.19 ˣ 10⁻¹²m
The increased potential is given by
Vₐc = hc/eλ = 6.625 × 10 ⁻³⁴ J,s) ( 3× 10⁸ m/s ( 1.6 ˣ 10 ⁻¹⁰C)
(7.19 ˣ 10⁻¹²m)
173kV.
Answer:
210 m
Explanation:
Given:
a = -6.8 m/s²
v₀ = 54 m/s
v = 0 m/s
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx
Δx ≈ 210 m
