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slava [35]
3 years ago
6

What type of mixture is fog?

Chemistry
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

. A homogeneous mixture of a solid in a gas

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Multiple Choice Questions 1. Which of the following statement best describes an atom? A. Protons and electrons are grouped toget
Arturiano [62]

Answer:

C is Correct

Explanation:

Protons and Neutrons make up the Nucleus while Electrons surround the nucleus in circular orbits with continuous rotation.

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2 years ago
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A topographical map would be useful for which activity? A. planning a hiking trip B. studying plant growth over time C. studying
amm1812
The answer is A. planning a hiking trip

A topographical map would not help studying plant growth over time unless you are looking for a better altitude to plant said plants.

A topographical map would not help studying rainfall for one year unless your location was <em>really</em> so high or low that it affected your weather

And most of all, a topographical map would not be useful for planning a cuise across the Atlantic Ocean because the elevation of the sea is zero!

A topographical map <em>would</em> be useful for planning a hiking trip because there are many factors and details that a hike should have. Which includes height, distance, paths, and elevation.
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3 years ago
The graph above plots gravitational force versus distance for two asteroids of equal mass (10 billion kg). When the distance bet
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Answer:ABOUT 74 N

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7 0
3 years ago
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The rate constant k for a certain reaction is measured at two different temperatures:
bogdanovich [222]

Answer:

Ea=5.5 Kcal/mole

Explanation:

Let rate constant are K_1  and K_2  at temperature T_1  and T_2

By using Arrhenius equation at two different two different temperature,

Log K_1/K_2 =E_a/2.303R*(1/T_2 -1/T_2 );T_1=273+376=649K  ;K_1=4.8*10^8;T_2=273+280=553K  ;K_2=2.3*10^8;R=2 cal/(mole.K);Log (4.8*10^8)/(2.3*10^8 )=E_a/2.303R*(1/553K-1/649); Log 4.8/2.3=E_a/2.303R*96/358897 ;0.32=E_a/2.303R*96/358897;E_a=(0.32*2.303R*358897)/96;  

By putting value of R=2 cal/mole.K

E_a=5510.265cal/mole;

By rounding off upto 2 significant figure;

E_a=5.5Kcal/mole;

8 0
3 years ago
You now know that [Pb+2] = 0.17 M. Calculate [Cl-].
iris [78.8K]

Answer:

0.34 M

Explanation:

I assume that the compound is PbCl2.

One mole of PbCl2 contains one mol of Pb+2 and 2 moles of Cl-

Molarity (M)= moles (n) /Volume (V)

Moles Pb2+ = M x V = 0.17 V

Moles Cl- = moles Pb2+ x (2 moles Cl-/1 mole Pb2+) = 0.17 V x 2 = 0.34 V

M Cl- = moles Cl-/V = 0.34V/V = 0.34 M

6 0
3 years ago
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