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slava [35]
3 years ago
6

What type of mixture is fog?

Chemistry
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

. A homogeneous mixture of a solid in a gas

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7.5 moles of nitrogen gas (N2) is formed in the following reaction. How many grams
AfilCa [17]

Answer:

Mass = 255 g

Explanation:

Given data:

Number of moles of nitrogen = 7.5 mol

Mass of ammonia formed = ?

Solution:

Chemical equation:

3H₂ + N₂      →    2NH₃

Now we will compare the moles of nitrogen and ammonia.

             N₂         :        NH₃

               1          :         2

              7.5       :       2/1×7.5 = 15

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 15 mol × 17 g/mol

Mass = 255 g

6 0
3 years ago
On a hot summer day, air rises most quickly when it is above a
NNADVOKAT [17]

Answer:

air rises most quikly above water so i'm confuse it's lake or river

6 0
3 years ago
Read 2 more answers
What is the maximum number of electrons in p&q shell​
Bad White [126]

Answer:

6 electrons

Explanation:

:)

hope this helps :))))))))

5 0
3 years ago
Read 2 more answers
How many moles are in 8.32 times 1024 molecules of CO2
Svetradugi [14.3K]

Answer:

13.8 mol CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

8.32 × 10²⁴ molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />8.32 \cdot 10^{24} \ molecules \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ molecules \ CO_2} ) = 13.816 mol CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

13.816 mol CO₂ ≈ 13.8 mol CO₂

3 0
3 years ago
How many molecules are there in 4.00 l of oxygen gas at 500.∘ c and 50.0 torr?
Oliga [24]
From  the  ideal  gas law   
pv=nRT , n  is  therefore PV/RT
R is  the
R is  gas  constant =62.364 torr/mol/k
P=500torr
 V=4.00l
T=500+273=773k
n={(500 torr x 4.00l)/(62.364 x773k)}=0.041moles
the  number  of  molecules=moles  x avorgadro costant that is  6.022x10^23)
6.022 x 10^23)  x0.041=2.469 x10^22molecules
3 0
3 years ago
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