On average, seawater in the world's oceans has a salinity of ~3.5%. This means that for every 1 litre (1000 mL) of seawater there are 35 grams of salts (mostly, but not entirely, sodium chloride) dissolved in it.
<h3>What is salinity ?</h3>
The saltiness or quantity of dissolved salt in a body of water is known as salinity (see also soil salinity). The standard units of measurement are grams of salt per liter (g/L) or grams per kilogram (g/kg; the latter is dimensionless and equal to ).
Salinity is a thermodynamic state variable that, along with temperature and pressure, controls physical properties like the density and heat capacity of the water. Salinity plays a significant role in determining many aspects of the chemistry of natural waters and of biological processes within them.
An isohaline, or isohale sometimes, is a contour line with a constant salinity.
The concept of salinity in rivers, lakes, and the ocean is straightforward, but it is difficult to define and measure properly on a scientific level.
To learn more about salinity from the given link:
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Answer:
i think the answer might be A the frist one
Explanation: because the chemical started immediately when the girl put in the two red colored and it started turning blue and by eight minutes it turned blue completely.
Answer:
1.39
Explanation:
[Hg2Cl2]= 1M
[H^+] = ????
E°cell= 0.35V
E= 0.268 V
Therefore E for the reaction must -0.082 V
n= 2 moles of electrons
From Nernst Equation:
E= E°cell- 0.0592/n log [Red]/[Ox]
0.0268= 0.35- 0.0592/2 log 1/[Ox]^2
-0.082= -0.0296 log 1/[Ox]^2
log 1/[Ox]^2= 0.082/0.0296
log 1/[Ox]^2= 2.77
1/[Ox]^2=Antilog (2.77)
[Ox]^2=1.698×10^-3
[Ox] = 0.0412 M
But pH= -log [H^+]= -log(0.0412)= 1.385
Answer:
Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
Explanation:
Let's apply the formula for freezing point depression:
ΔT = Kf . m
ΔT = 74.2°C - 73.4°C → 0.8°C
Difference between the freezing T° of pure solvent and freezing T° of solution
Kf = Cryoscopic constant → 5.5°C/m
So, if we replace in the formula
ΔT = Kf . m → ΔT / Kf = m
0.8°C / 5.5 m/°C = m → 0.0516 mol/kg
These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg
0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:
Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
The question to your answer would be either a or C
