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Alex17521 [72]
3 years ago
13

Which of the following correctly pairs the subatomic particle with its charge?

Physics
2 answers:
jarptica [38.1K]3 years ago
6 0

Answer: b:

Explanation:

protons are positive,

electrons are negative,

and neutrons are neutral.

the amount of electrons to protons is always the same in a balanced atom.

electrons can be removed creating "ions" which is simply an unbalanced atom. removing protons would result in a different type of atom or element.

Margarita [4]3 years ago
4 0
The answer that’s your looking for is C
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A ball is thrown at an angle of 38 degrees to the horizontal. What happens to the magnitude of the ball's vertical acceleration
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7 0
2 years ago
Is it possible to produce a continuous and oriented aramid fiber–epoxy matrix composite having longitudinalandtransverse moduli
Masja [62]

Answer:

Not possible

Explanation:

E_{cl} = longitudinal modulus of elasticity = 35 Gpa

E_{ct} = transverse modulus of elasticity = 5.17 Gpa

E_m = Epoxy modulus of elasticity = 3.4 Gpa

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V_{\rho t} = Volume fraction of fibre (transvers)

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Longitudinal modulus of elasticity is given by

E_{cl}=E_m(1-V_{\rho l})+E_fV_{\rho l}\\\Rightarrow 35=3.4(1-V_{\rho l})+131V_{\rho l}\\\Rightarrow 35=3.4-3.4V_{\rho l}+131V_{\rho l}\\\Rightarrow V_{\rho l}=\frac{35-3.4}{131-3.4}\\\Rightarrow V_{\rho l}=0.24764

Transverse modulus of elasticity is given by

E_{ct}=\frac{E_mE_f}{(1-V_{\rho t})E_f+V_{\rho t}E_m}\\\Rightarrow 5.17=\frac{3.4\times 131}{(1-V_{\rho t})131+V_{\rho t}3.4}\\\Rightarrow \frac{3.4\times 131}{5.17}-131=-127.6V_{\rho t}\\\Rightarrow V_{\rho t}=\frac{\frac{3.4\times 131}{5.17}-131}{-127.6}\\\Rightarrow V_{\rho t}=0.35148

V_{\rho l}\neq V_{\rho t}

Hence, it is not possible to produce a continuous and oriented aramid fiber.

5 0
3 years ago
An unbalanced force gives a 2.00 kg mass an acceleration of 5.00 m/s? What is the force applied to the object?​
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Answer:

10N

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Equation: ΣF = ma

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Fapp = 10*kg*m/s^2

Fapp = 10N

5 0
2 years ago
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ale4655 [162]

Answer:

All i kno is that that kid ain't gonna be ok

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