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Juli2301 [7.4K]
4 years ago
15

A bicycle coasts along a flat road. what form of energy does it best demonstrate ​

Physics
1 answer:
xeze [42]4 years ago
4 0

Answer:

Kinetic energy

hope this helps:))

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Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which
notka56 [123]

Answer:

a=5.66*10^{23} \frac{m}{s^2}

Explanation:

In this case we will use the Bohr Atomic model.

We have that: F=m*a

We can calculate the centripetal force using the coulomb formula that states:

F=k*\frac{q*q'}{r^2}

Where K=9*10^9 \frac{Nm^2}{C}

and r is the distance.

Now we can say:

m*a=k*\frac{q*q'}{r^2}

The mass of the electron is = 9.1*10^{-31} Kg

The charge magnitud of an electron and proton are= 1.6*10^{-19}C

Substituting what we have:

[tex]a=\frac{9*10^{9}*(1.6*10^{-19} )*(2(1.6*10^{-19} ))}{9.1*10^{-31}*(2.99*10^{-11})^2 }[/tex]

so:

a=5.66*10^{23} \frac{m}{s^2}

3 0
3 years ago
NaOH is__<br> an acid <br> a base <br> a salt
masya89 [10]

Answer:

Sodium Hydroxide

Explanation:

4 0
4 years ago
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What emits infrared radiation?
Nimfa-mama [501]

Answer:

anything that contains atoms is the correct answer of given statement

3 0
2 years ago
Two point charges of +20.0 μC and -8.00 μC are separated by a distance of 20.0 cm. What is the intensity of electric field E mid
algol13

Answer:

The intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

Explanation:

Here we need first find the electric field due to the first charge at the midway point.

The electric field equation is given by:

|E_{1}|=k\frac{q_{1}}{d^{2}}

Where:

  • k is Coulomb's constant
  • q(1) is 20.00 μC or 20*10⁻⁶ C
  • d is the distance from q1 to the midpoint (d=10.0 cm)

So, we will have:

|E_{1}|=(9*10^{9})\frac{20*10^{-6}}{0.1^{2}}

|E_{1}|=1.8*10^{7}\: N/C

The direction of E1 is to the right of the midpoint.

Now, the second electric field is:

|E_{2}|=k\frac{q_{2}}{d^{2}}

|E_{2}|=(9*10^{9})\frac{8*10^{-6}}{0.1^{2}}

|E_{2}|=7.2*10^{6}\: N/C

The direction of E2 is to the right of the midpoint because the second charge is negative.

Finally, the intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

I hope it helps you!

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3 years ago
You are having a snowball fight with your best friend on a frosty winter day. You are standing on the roof of your 5 m tall hous
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In my own opinion I think it’s c
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