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3 years ago

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A device for exercising the upper leg muscle is shown above, together with a schematic representation of an equivalent lever sys

tem. calculate the force exerted by the upper leg muscle to lift the mass at a constant speed.

1 answer:

yuradex [85]3 years ago

4 0

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Please help me.

vesna_86 [32]

A) the tension in the string.

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3 years ago

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Which is an example of an unintentional injury? A student decides to cut herself. Two people have a domestic dispute that leads

slavikrds [6]

I think its the last one, a student slips on the ice in front of school and sprains his ankle. An example of a natural fiber could be cotton B.

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3 years ago

What is the average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8

Alex

Answer:

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 $\frac{m}{s}$ .

Explanation:

Velocity is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

$velocity=\frac{displacement}{time}$

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.

In this case, the displacement is 192 m and the time period is 8 s. Replacing:

$velocity=\frac{192 m}{8 s}$

Solving:

velocity= 24 $\frac{m}{s}$

<em><u>The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 </u></em> $\frac{m}{s}$ <em><u>.</u></em>

3 0

3 years ago

A rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind

34kurt

Answer:

Answer for the question is given in the attachment.

Explanation:

4 0

3 years ago

A 34-m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 68 A and experiences a

il63 [147K]

Answer:

7.28×10⁻⁵ T

Explanation:

Applying,

F = BILsin∅............. Equation 1

Where F = magnetic force, B = earth's magnetic field, I = current flowing through the wire, L = Length of the wire, ∅ = angle between the field and the wire.

make B the subject of the equation

B = F/ILsin∅.................. Equation 2

From the question,

Given: F = 0.16 N, I = 68 A, L = 34 m, ∅ = 72°

Substitute these values into equation 2

B = 0.16/(68×34×sin72°)

B = 0.16/(68×34×0.95)

B = 0.16/2196.4

B = 7.28×10⁻⁵ T

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2 years ago