Answer:
![\left[\begin{array}{ccc}7\\4\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C4%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
The answer is a single-column matrix (7,4,2)
Step-by-step explanation:
In such multiplication of matrices, you have to proceed by multiplying each ROW of the first matrix by the COLUMN of the second matrix. So,
![\left[\begin{array}{ccc}3&6&1\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (3 * 2) + (6 * 0) + (1 * 1) = 6 + 0 + 1 = 7](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%261%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C0%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%3D%20%283%20%2A%202%29%20%2B%20%286%20%2A%200%29%20%2B%20%281%20%2A%201%29%20%3D%206%20%2B%200%20%2B%201%20%3D%207)
then...
![\left[\begin{array}{ccc}2&4&0\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (2 * 2) + (4 * 0) + (0 * 1) = 4 + 0 + 0 = 4](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%264%260%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C0%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%3D%20%282%20%2A%202%29%20%2B%20%284%20%2A%200%29%20%2B%20%280%20%2A%201%29%20%3D%204%20%2B%200%20%2B%200%20%3D%204)
and
![\left[\begin{array}{ccc}0&6&2\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (0 * 2) + (6 * 0) + (2 * 1) = 0 + 0 + 2= 2](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%266%262%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C0%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%3D%20%280%20%2A%202%29%20%2B%20%286%20%2A%200%29%20%2B%20%282%20%2A%201%29%20%3D%200%20%2B%200%20%2B%202%3D%202)
I hope it helps.
Answer:
Its a i just took the test
Step-by-step explanation:
Answer:
13.44
Step-by-step explanation:
she is right...........
Answer:
5x+6y=60
Step-by-step explanation:
x= $5 per pound of second type of seed
y=$6 per pound of first types of seed
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
