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erastovalidia [21]
3 years ago
5

Density is the ratio of an object’s mass to its volume. would you expect density to be a vector or a scalar quantity? explain.

Physics
1 answer:
natali 33 [55]3 years ago
4 0
Vectors are quantities described by a number and a direction, thus giving them a line value. these include acceleration, velocity and weight
Scalar quantities only have a magnitude and include things like volume, distance and temperature. Because density uses volume and mass, it is considered a scalar.
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A uniform rod of length 0.7 m and mass 10 kg rotates freely about a horizontal axis passing through one end of the rod a bullet
mars1129 [50]

Answer:

<u>ω = 1.7 rad/s</u>

Explanation:

Conservation of angular momentum

Assuming the rod is initially hanging vertically at rest.

Initial angular momentum is carried by the bullet only

L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s

the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²

2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω

2.8 = (1.64313333...)ω

ω = 1.70406134...

3 0
3 years ago
Consider a series LRC-circuit in which C-120.0 uF. When driven at a frequency w = 200.0 rad s-1 the com ples impedance is given
Lina20 [59]

Answer:

(a). (i). The reactants are X_{L} =31.66\ \Omega .

(II). The inductance of the circuit is 0.1583 Henry.

(b). The resonant angular frequency is 229.4 rad/s.

Explanation:

Given that,

Capacitor = 120.0 μC

Frequency = 200.0 rad/s

Impedance = 100.0 -10j

(I). We need to calculate the X_{C}

X_{C}=\dfrac{1}{C\times\omega}

Put the value into the formula

X_{C}=\dfrac{1}{120\times10^{-6}\times200}

X_{C}=41.66\ \Omega

(II). We know that,

Formula of impedance is

Z=\sqrt{R^2+X_{L}^2+X_{C}^2}...(I)

Given equation of impedance is

Z=(100-10j)...(II)

On Comparing of equation (I) and (II)

R = 100

X_{L}-X_{C}=-10

Now, put the value of  X_{C}

X_{L=41.66-10

X_{L}=31.66\ \Omega

We need to calculate the inductance

Using formula of inductance

X_{L}=\omega\times L

Put the value into the formula

L=\dfrac{X_{L}}{\omega}

L=\dfrac{31.66}{200}

L=0.1583\ Henry

(b). We need to calculate the resonant angular frequency

Using formula of the resonant angular frequency

angular\ frequency =\dfrac{1}{\sqrt{L\times C}}

angular\ frequency =\dfrac{1}{\sqrt{0.1583\times120\times10^{-6}}}

angular\ frequency =229.4\ rad/s

Hence, (a). (i). The reactants are X_{L} =31.66\ \Omega .

(II). The inductance of the circuit is 0.1583 Henry.

(b). The resonant angular frequency is 229.4 rad/s.

4 0
3 years ago
What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-
sergey [27]

q = -21 * 10^{-6} C

<h3>What is Free-fall acceleration?</h3>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\

and its sign must be negative so that it will have upward electric force

so it is

q = -21 * 10^{-6} C

The charge of a particle of mass is -21 * 10^{-6} C

Learn more about Free-fall acceleration: brainly.com/question/2165771

#SPJ1

8 0
2 years ago
What happens to temperature as a substance melts and heat energy is used to break the connections between molecules, until all m
zaharov [31]

Answer:

Stays the same.

Explanation:

The temperature does not change just because something melts.

3 0
3 years ago
Un semáforo de 80N cuelga del punto medio de un cable de 30m tendido entre 2 postes. Halle la tensión en cada segmento del cable
olganol [36]

Answer:

T1 = T2 = 602.33 N

Explanation:

I attached an image of the forces diagram below.

The x component of the forces for this cases is:

\Sigma F_x=T_1cos\theta-T_2cos\theta=0\\\\T_1cos\theta=T_2cos\theta\\\\T_1=T_2

And the y components:

\Sigma F_y=T_1sin\theta+T_2sin\theta-W=0\\\\T_1=T_2=T\\\\\Sigma F_y=2Tsin\theta=W\\\\T=\frac{W}{2sin\theta}

The angle is calculated by using the information about the length of the cable and the vertical distance of the traffic light:

\theta=tan^{-1}(\frac{1}{15})=3.81\°

Thus, you obtain:

T=\frac{80N}{2(sin3.81\°)}=601.33N

hence, the tension in both segments of the cable is 602.33 N

3 0
3 years ago
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