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3 years ago

Please help me at this math proplem thank you pleas help me

Mathematics

1 answer:

Shkiper50 [21]3 years ago

4 0

which math problem?? There is many on the picture

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Sweet Treats Bakery sells gourmet cookies. If three gourmet cookies cost $7.95, then

Lynna [10]

Answer:

$26.50

Step-by-step explanation:

7.95/3=2.65

2.65*10=26.5

4 0

2 years ago

Read 2 more answers

If ru is an altitude of rst find rs

Anna11 [10]

Answer:

The correct answer is Option D. 20

Step-by-step explanation:

From the figure we get,

<RUS = 90° because RU ⊥ TS

To find the value of x

It is given that <RUS = 4x + 54

Therefore we can write,

4x + 54 = 90

4x = 90 - 54 = 36

x = 36/4 = 9

To find RS

It is given that,

RS = 3x - 7 = 3*9 -7 = 20

Therefore the correct option is Option D . 20

4 0

3 years ago

Solve for x and explain the steps: 3x-6=4(2-3x)-8x

mote1985 [20]

Answer: x = 14/23

Step-by-step explanation:

3x-6=4(2-3x)-8x

3x-6=8-12x-8x --> Expand 4(2-3x)

3x-6=8-20x --> Collect like terms

3x-6+6=8-20x+6 --> Add 6 to both sides, to remove it from the right side

3x=-20x+14

3x+20x=-20x+14+20x --> Add 20x to both sides, to remove it from the left side

23x=14

$\frac{23x}{23}=\frac{14}{23}$ --> Divide both sides by 23

x = 14/23

7 0

2 years ago

The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu

rjkz [21]

The balloon has a volume $V$ dependent on its radius $r$ :

$V(r)=\dfrac43\pi r^3$

Differentiating with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}$

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

$10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}$

The surface area of the balloon is

$S(r)=4\pi r^2$

and differentiating gives

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}$

so that at the moment the radius is 3 m, its area is increasing at a rate of

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}$

4 0

2 years ago

There are 205 coins in a jar all of which are either nickles or quarters . The vaule of the coin in the jar is $31.85. if both o

Gnesinka [82]

Answer: There are 97 nickels and 108 quarters.

Step-by-step explanation:

Let x = Number of nickels, y = Number of quarters.

As per given,

x+y = 205 ...(i)

0.05x+0.25y = 31.85 ... (ii) [1 nickel = $0.05, 1 quarter = $ 0.25]

Multiply (ii) by 20, we get

x+5y=637 ...(iii)

Eliminate (i) from (iii)

4y = 432

⇒ y = 108 [Divide both sides by 4]

Put value of y in (i), we get

$108+x=205\Rightarrow\ x= 97$

Hence, there are 97 nickels and 108 quarters.

6 0

3 years ago