For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
Answer:
Shade above 2x + y = 4.
Shade below 2x + y = 4.
Shade above 2y = 6 – 2x.
Shade below 2y = 6 – 2x.
Make the boundary line 2x + y = 4 dashed.
Step-by-step explanation:
:D i hav th same question cuz i hav lik 3 E's
probably one failing grade each quarter or marking period w.e ur school calls it
ik in my school i cn get honor role even tho i hav one C soooo ^thts wat im thinkin
The first step to solving this problem is to plug in 6 where you see a in the expression
-6² - 6 (-6) + 4
the first step to solving this is to evaluate the power
-36 - 6x (-6) + 4
next you will multiply the numbers
-36 + 36 + 4
finally,, eliminate the opposite of the expression to find your answer
4
this means that the correct answer to your question is 4.
let me know if you have any further questions
:)
