Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
We have been given that :-
The length of a parasite in experiment A is 
The length of a parasite in experiment B is 
Let us write the the length of the parasite in experiment A in the exponent of -3.
Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.
The difference in the length is given by
Therefore, the length of the parasite in experiment A is inches greater than the length of the parasite in experiment B.
1) Venn Diagram is used to organize data
2) Four circles. Three intersection circles, and one which contains other three circles
3) In the intersection area of three circles.
4) In the circle which contains other three circles, but not inside any of the intersecting circles.
Answer:
a=-22
Step-by-step explanation:
Multiply both sides of the negative equation by (-2) to get the equation:
a-4=13(-2)
then simplify to get:
a-4=-26
then isolate the variable by addig 4 to both sides of the equation to get:
a=-26+4
simplify to get:
a=-22
