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3 years ago

What is the domain of h???????HELPPP!!!!

Mathematics

1 answer:

Gwar [14]3 years ago

3 0

The domain is all possible x values.

In this case it goes from -2 to 6

So your domain is [-2,6] which is option b

Since the values -2 and 6 are included you use greater than or equal to and less than or equal to.

I

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If sin =1/2then show that 3cos -4cos^3=0z

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Step-by-step explanation:

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3 years ago

How much fencing is needed to make the cage area?

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3 years ago

Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact

scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

H₀: The variance of speeds does not exceeds 75 (mph)², i.e. σ² ≤ 75.

Hₐ: The variance of speeds exceeds 75 (mph)², i.e. σ² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, α = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

$\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153$

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

$\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}$

$=\frac{(55-1)\times 94.7}{75}\\\\=68.184$

The test statistic value is, 68.184.

Decision:

$cal.\chi^{2}=68.184$

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

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3 years ago

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zaharov [31]

I don’t understand

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3 years ago

A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether th

ki77a [65]

Answer:

(a) A matched pair design is used to perform the test.

(b) Each sample is of size 30.

(d) The effect size of the test is medium.

Step-by-step explanation:

A statistical experiment is performed to determine whether the amount of time (in minutes) that parent-child pairs spend on social networking sites to test show any generational differences.

Given:

MD = -42 minutes

t₍₂₉₎ = 4.021

p < 0.05

d = 0.49

The hypothesis is:

H₀: There is no difference between the means, i.e. μ₁ = μ₂.

Hₐ: There is a significant difference between the means, i.e. μ₁ ≠ μ₂.

(a)

A matched pair design is used to perform the test.

In a matched pair design the participant of the two groups are related in some way. For example, the same sample is tested before and after applying the treatment.

In this case the matched are pairs are of children and their parents. And the treatment is the amount of time spent on social networking sites.

(b)

The degrees of freedom of a matched pair design is:

df = n - 1

29 = n - 1

n = 29 + 1

n = 30

Thus, each sample is of size 30.

(c)

The p-value of the test statistic is < 0.05.

If the p-value is less than the significance level α (say, 0.05) then the null hypothesis is rejected and vise-versa.

Since p < 0.05 the null hypothesis is rejected concluding that there is a significant difference between the amount of time spent on social networking sites by parents and children.

(d)

The estimated value of Cohen's d is, d = 0.49.

A Cohen's d value between the range 0.50 to 0.80 is considered as medium.

Thus, the effect size of the test is medium.

3 0

3 years ago