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8090 [49]
3 years ago
6

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0

.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?
Chemistry
1 answer:
Lena [83]3 years ago
3 0

Answer:

6.096799125kg

Explanation:

According to the question, three different samples weighed using different types of balance had masses: 0.6160959 kg, 3.225 mg, and 5480.7 g.

Based on observation, the mass units in the three measurements are different but must be uniform in order to find the total mass. Hence, we need to convert to the standard unit (S.I unit of mass), which is kilograms (kg)

Since 1kg equals 1,000,000mg

Hence, 3.225mg will be 3.225/1000000

= 0.000003225kg

Also, 1kg equals 1000g

Hence, 5480.7g will be 5480.7/1000

= 5.4087kg

Hence, the total mass of the three samples (now in the same unit) are:

5.4807kg + 0.000003225kg + 0.6160959 kg

= 6.096799125kg

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What volume of a 6.0m hcl solution is required to make 250.0 milliters of 1.5 m hcl
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Answer : The volume for 6.0m HCl solution required = 62.5 ml

Solution : Given,

Initial concentration of HCl solution = 6.0m

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Initial volume of HCl solution = ?

Formula used for dilution is,

M_1V_1=M_2V_2

where,

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6.0m\times V_1=1.5m\times 250ml

V_1 = 62.5 ml

Therefore, the volume for 6.0m HCl solution required = 62.5 ml


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