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rjkz [21]
3 years ago
10

The 10 foot wide circle quarter gate AB is articulated at A. Determine the contact force between the gate and the smooth surface

at B due to the pressure of the water acting on the gate. Use γ = 62.4 lb / ft^3 for the water. R=8 ft
Engineering
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

F = 641,771.52 \dfrac{lb-ft}{s^2}

Explanation:

Given that

R=8 ft

Width= 10 ft

We know that hydro statics force given as

  F=ρ g A X

ρ is the density of fluid

A projected area on vertical plane

X is distance of center mass of projected plane from free surface of water.

Here

X=8/2  ⇒X=4 ft

A=8 x 10=80  ft^2

So now putting the values

F=ρ g A X

F=62.4(32.14)(80)(4)

F = 641,771.52 \dfrac{lb-ft}{s^2}

   

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