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kaheart [24]
2 years ago
11

What does the rate law tell you about a reaction?

Chemistry
1 answer:
natta225 [31]2 years ago
8 0

Answer:

A. How the concentration of the reactants affects the rate of a reaction

Explanation:

Let's consider a generic reaction.

A + B ⇒ Products

The generic rate law is:

rate  = k × [A]ᵃ × [B]ᵇ

where,

  • rate: rate of the reaction
  • [A] and [B]: molar concentrations of the reactants
  • k: rate constant
  • a and b: reaction orders

As we can see, the rate law shows how the concentration of the reactants affects the rate of a reaction.

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Answer:

ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.

Explanation:

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What is the best conclusion according to the energy diagram of the chemical reaction?
Mariulka [41]

"The reaction will absorb energy" is the best conclusion according to the energy diagram of the chemical reaction.

<u>Option: B</u>

<u>Explanation:</u>

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5 0
3 years ago
A second-order reaction has a rate law: rate = k[a]2, where k = 0.150 m−1s−1. If the initial concentration of a is 0.250 m, what
Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s

To determine:

Concentration at time t = 300 s i.e. [a]_{t}

Calculations:

The second order rate equation is:

1/[a]_{t} = kt +1/[a]

substituting for k,t and [a] we get:

1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M

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[a]t = 1/49 M-1 = 0.0204 M

Hence the concentration of 'a' after t = 5min is 0.020 M



7 0
3 years ago
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