1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irga5000 [103]
3 years ago
9

A liquid phase chemical reaction (A → B) takes place in a well-stirred tank. The concentration of compound A in the feed is CA0

(mol/m3 ), and that in the outlet stream is CA (mol/m3 ). Neither concentration varies with time. The volume of the tank contents is V (m3) and the volumetric flow rate of the inlet and outlet streams is Ẇ (m3 /sec). The reaction rate (the rate at which A is consumed by reaction in the tank) is given by the expression r (mol A consumed/s) = kVCA wherek is a constant.
(a) Is this process continuous, batch, or semi batch? Is ittransient or steady - state?(b) What would you expect the reactant concentrationCA to equal if k = 0 (no reaction) ? What should itapproach if k [infinity] ( infinitely rapid reaction) ?(c) Write a differential balance on A, starting which terms inthe general balance equation ( accumulation = input + generation -output - consumption) you discarded and why you discarded them. Usethe balance to derive the following relation between the inlet andoutlet reactant concentrations :CA = CA0 / (1 + kV/ ). Verify that this relation predicts the results in part(b).
Engineering
1 answer:
SCORPION-xisa [38]3 years ago
4 0

Answer:

EH buddy use a sparkplug use a drill through a hose im from da bronx

Explanation:

You might be interested in
A 200‑m rigid vessel contains a saturated liquid‑vapor mixture with a vapor quality of 75%. The temperature of the vessel is mai
DerKrebs [107]

Answer:

Given,

Temperature;

T = 393;;K

Convert to Celcius;

T = (393-273) degrees

T = 120°C

Using Table A-4 (Saturated water - Temperature table), at T = 120 C;

vf = 0.001060 m³/kg

vg = 0.89133 m³/kg

Quality is given as;

75% = 0.75

Specific volume is given as;

v = vf + x (vg - vf) = 0.001060 + 0.75(0.89133 _ 0.001060)

v= 0.66876 m³/kg

We know;

v = V/m

0.66876  = 100/m

m = 149.53 kg

6 0
3 years ago
Steam enters a two-stage adiabatic turbine at 8 MPa and 5008C. It expands in the first stage to a state of 2 MPa and 3508C. Stea
Nataly [62]

Answer:

1) The exergy of destruction is approximately 456.93 kW

2) The reversible power output is approximately 5456.93 kW

Explanation:

1) The given parameters are;

P₁ = 8 MPa

T₁ = 500°C

From which we have;

s₁ = 6.727 kJ/(kg·K)

h₁ = 3399 kJ/kg

P₂ = 2 MPa

T₂ = 350°C

From which we have;

s₂ = 6.958 kJ/(kg·K)

h₂ = 3138 kJ/kg

P₃ = 2 MPa

T₃ = 500°C

From which we have;

s₃ = 7.434 kJ/(kg·K)

h₃ = 3468 kJ/kg

P₄ = 30 KPa

T₄ = 69.09 C (saturation temperature)

From which we have;

h₄ = h_{f4} + x₄×h_{fg} = 289.229 + 0.97*2335.32 = 2554.49 kJ/kg

s₄ =  s_{f4} + x₄×s_{fg} = 0.94394 + 0.97*6.8235 ≈ 7.563 kJ/(kg·K)

The exergy of destruction, \dot X_{dest}, is given as follows;

\dot X_{dest} = T₀ × \dot S_{gen} = T₀ × \dot m × (s₄ + s₂ - s₁ - s₃)

\dot X_{dest} = T₀ × \dot W×(s₄ + s₂ - s₁ - s₃)/(h₁ + h₃ - h₂ - h₄)

∴ \dot X_{dest} = 298.15 × 5000 × (7.563 + 6.958 - 6.727 - 7.434)/(3399 + 3468 - 3138  - 2554.49) ≈ 456.93 kW

The exergy of destruction ≈ 456.93 kW

2) The reversible power output, \dot W_{rev} = \dot W_{} + \dot X_{dest} ≈ 5000 + 456.93 kW = 5456.93 kW

The reversible power output ≈ 5456.93 kW.

6 0
3 years ago
The unit for volume flow rate is gallons per minute, but cubic feet per second is preferred. Use the conversion factor tables in
amm1812

Answer:

The conversion factor is 0.00223 ( 1 gallon per minute equals 0.00223 cubic feet per second)

Explanation:

Since the given volume flow rate is gallons per minute.

We know that 1 gallon = 3.785 liters and

1 minute = 60 seconds

Let the flow rate be Q\frac{gallons}{minute}

Now replacing the gallon and the minute by the above values we get

Q'=Q\frac{gallon}{minute}\times \frac{3.785liters}{gallon}\times \frac{1minute}{60seconds}

Thus Q'=0.631Q\frac{liters}{second}

Now since we know that 1 liter = 0.0353ft^{3}

Using this in above relation we get

Q'=0.631Q\frac{liters}{second}\times \frac{0.0353ft^3}{liters}\\\\\therefore Q'=0.00223Q

From the above relation we can see that flow rate of 1 gallons per minute equals flow rate of 0.00223 cubic feet per second. Thus the conversion factor is 0.00223.

3 0
3 years ago
Don't break or crush mercury-containing lamps because mercury powder may be released.
alexandr402 [8]
A.

It would be released without a doubt so be careful!

Hope this helps :)
5 0
4 years ago
Search and destroy christian
Setler [38]

Answer: ummmm wut?

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • The voltage across a device and the current through it are:
    9·2 answers
  • Consider the two wood pieces that are connected by a velcro as indicated below. The block is subjected to a tension force P and
    6·2 answers
  • 11. Which of the following is the brake fluid most often used?
    11·2 answers
  • In the circuit given below, R1 = 17 kΩ, R2 = 74 kΩ, and R3 = 5 MΩ. Calculate the gain 1formula58.mml when the switch is in posit
    7·1 answer
  • Acquisition of resources from an external source is called?
    15·1 answer
  • The point of contact of two pitch circles of mating gears is called?
    10·1 answer
  • What are three types of land reform ​
    10·2 answers
  • 1. Springs____________<br> energy when compressed<br> And _________energy when they rebound.
    12·1 answer
  • A(n)<br> is a safety device commonly<br> used with a slotted nut.
    14·1 answer
  • Valorant Or Csgo? which is best in your opinion?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!