How to update android 4.4.2 to 5.1

Calculate the diameter of pneumatic cylinder to drive a mechanism. The force exerted by the mechanism is 80 N. The return force

sashaice [31]

Answer:

14.27 mm

Explanation:

Force = 80 Newton

Pressure exerted = 5 bar = 5×10⁵ Pa

Pressure exerted = Force/Area

Area = Force/Pressure

$Area=\frac{80}{500000}\\\Rightarrow Area=0.00016\ m^2$

Area of the cylinder=πd²/4

$\Rightarrow \frac{\pi}{4}d^2=0.00016\\\Rightarrow d^2=\frac{4\times 0.00016}{\pi}\\\Rightarrow d^2=0.0002037\\\Rightarrow d=0.01427\ m$

Hence diameter of cylinder 14.27 mm

5 0

3 years ago

You will create three classes, the first two being Student and LineAtOfficeHour. The instances of the first class defines a sing

White raven [17]

Answer:

Complete solution is given below:

Explanation:

//student class

class Student{

private String firstname,lastname;

//constructor

Student(String first,String last){

this.firstname=first;

this.lastname=last;

}

//getters and setters

public String getFirstname() {

return firstname;

}

public void setFirstname(String firstname) {

this.firstname = firstname;

}

public String getLastname() {

return lastname;

}

public void setLastname(String lastname) {

this.lastname = lastname;

}

//function to get the fullname of student

public String fullName() {

return this.firstname+" "+this.lastname;

}

//class for line at office hour

class LineAtOfficeHour{

private Student line[];

private int N=0;

private int back=0;

//empty constructor

LineAtOfficeHour() {

line=new Student[5];

}

//parameterized constructor

LineAtOfficeHour(Student st[]) {

int i=0;

line=new Student[5];

while(i<st.length && i<5) {

line[i]=st[i];

i++;

}

this.N=i;

this.back=i-1;

}

//function to check if line is empty or not

public boolean isEmpty() {

if(this.N==0)

return true;

else

return false;

}

//function to check if line is full

public boolean isFull() {

if(this.N==5) {

return true;

}else

return false;

}

///function to get the size of line

public int size() {

return this.N;

}

//function to add a student to the line

public void enterLine(Student s) {

if(isFull())

System.out.println("Line is full!!!!");

else {

line[++back]=s;

this.N++;

}

public Student seeTeacher() {

Student result=null;

if(this.N>=0) {

result=line[0];

int i=0;

for(i=1;i<N;i++) {

line[i-1]=line[i];

}

line[i-1]=null;

this.N--;

this.back--;

}

return result;

}

//function to print students in line

public String whosInLine() {

String result ="";

for(int i=0;i<this.N;i++) {

result+=line[i].fullName()+",";

}

return result;

}

//driver method

public class TestLine {

public static void main(String[] args) {

LineAtOfficeHour list=new LineAtOfficeHour();

if(list.isEmpty()) {

System.out.println("Line is empty!!!!!!!!!");

}

Student s1[]=new Student[3];

s1[0]=new Student("John","Smith");

s1[1]=new Student("Sam","Zung");

s1[2]=new Student("Peter","Louis");

list=new LineAtOfficeHour(s1);

if(list.isEmpty()) {

System.out.println("Line is empty!!!!!!!!!");

}else {

System.out.println("Line is not empty.........");

}

System.out.println("Students in line: "+list.whosInLine());

System.out.println("Student removed: "+list.seeTeacher().fullName());

System.out.println("Students in line: "+list.whosInLine());

}

6 0

4 years ago

Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these d

Tems11 [23]

Complete Question

Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these devises are available for weekend warriors who want to play with their chain saws. Let us model the illustrated tongs as a planar mechanism that carries a log of weight 210 N. Given the following dimensions: 35 mm 10 mm 40 mm 230 mm 85 mm 45 mm 10 mm 35 mm 345 mm determine the force in N and moment in Nm that our worker exerts on the tongs. Also determine the pinching force magnitude in N that the tongs exert on the log; i.e. determine the horizontal force that the tong's teeth exert on the log. Assume the point E is centered between the tong's teeth.

The diagram for this question is shown on the first uploaded image

Answer:

The force P is $P= 210 N$

and the moment M is $M = -48.3N \cdot m$

The horizontal force that the tong teeth exerts is $F_T =89.67N$

Explanation:

First let denote the dimension to corresponding to the diagram

$a=35mm , b= 10mm, c= 40mm, d= 230mm, e= 85mm,f= 45mm,\\g= 10mm,h=35mm,i=345mm.$

Next looking at the diagram let us consider the vertical direction

At equilibrium

$\sum F_{vertical} =0$

This mean that

$P+ W = 0$

Since they are acting in opposite direction the equation becomes

$P - W = 0$

=> $P= W$

=> $P= 210 N$

At Equilibrium Moment about F gives

$\sum M_f = 0$

=> $F_T * (e +f + g+ h+ i) - F_T * (e+ f+g+ h+i) - W *d -M =0$

=> $M = -W *d$

=> $M = -210 * 0.230$

=> $M = -48.3N \cdot m$

Here $F_T$ is the horizontal force that the tong teeth exerts

Now let consider the part BAF of the system as shown on the second uploaded image

Now the angle $\theta$ is mathematically given as

$tan \theta = \frac{g+h}{a}$

=> $\theta = arctan \frac{g+h}{a}$

$= arctan (\frac{10+35}{35} )$

$=52.125^o$

Now at equilibrium the moment about A is

$\sum M_A = 0$

=> $P * (c+d) +M + F_{BC} cos \theta *f+F_{BC}sin\theta *(a+b) =0$

$210 * (0.040 + 0.230)-48.3+F_{BC} cos (52.125^o)*0.045+ F_{BC}sin(52.125^o)$ $* (0.035 +0.010) =0$

=> $10.29 +F_{BC} (0.02763+0.03552) =0$

=> $F_{BC} =\frac{10.29}{0.06315}$

=> $F_{BC} = - 162.925 N$

Looking at the forces acting on the teeth as shown on the third uploaded image

At Equilibrium the moment about D is

$\sum M_D = 0$

=> $\frac{W}{2} *d - F_T *(i+h) -F_{BC} cos \theta *h -F_{BC} sin \theta * (b+c) =0$

=> $\frac{210}{2} * 0.230 -F_T (0.345 +0.035) - (-162.925)cos(52.125^o) *0.035\\-(-162.925)sin(52.125^o)(0.010 +0.040) =0$

=> $34.081 = F_T(0.345 +0.035)$

=> $F_T =89.67N$

7 0

4 years ago

Which of the following is a true statement about falling object safety?

Anastaziya [24]

Answer:

regregregrega

Explanation:

a

6 0

3 years ago

A 50 kg diver stands motionless at the top of 10.0 meter high dive. What is her potential energy?

brilliants [131]

Answer:

Potential energy=4905 Joule

Explanation:

Potential energy is defined as the energy between two bodies due to its relative positions. Here one body is the diver and the other body is the earth. So acceleration will be the constant $9.81\ m/s^2$

$P.E.=m\times g\times h\\where\ m=mass\ of\ body=50\ kg\\g=acceleration\ due\ to\ gravity=9.81\ m/s^2\\h=height\ at\ which\ the\ body\ is\ from\ the\ ground=10.0\ m\\\Rightarrow P.E.=50\times 9.81\times 10.0\\\therefore Potential\ Energy=4905\ Joule$

7 0

4 years ago

How to update android 4.4.2 to 5.1​

How to update android 4.4.2 to 5.1