Answer:
<em>55%</em>
Explanation:
hot reservoir = 1100 K
cold reservoir = 500 K
<em>This is a Carnot system</em>
For a Carnot system, maximum efficicency of the system is given as
Eff = 1 - 
where Tc = temperature of cold reservoir = 500K
Th = temperature of hot reservoir = 1100 K
Eff = 1 - 
Eff = 1 - 0.45 = 0.55 or<em> 55%</em>
Answer:
percentage change in volume is 2.60%
water level rise is 4.138 mm
Explanation:
given data
volume of water V = 500 L
temperature T1 = 20°C
temperature T2 = 80°C
vat diameter = 2 m
to find out
percentage change in volume and how much water level rise
solution
we will apply here bulk modulus equation that is ratio of change in pressure to rate of change of volume to change of pressure
and we know that is also in term of change in density also
so
E =
................1
And
............2
here ρ is density
and we know ρ for 20°C = 998 kg/m³
and ρ for 80°C = 972 kg/m³
so from equation 2 put all value


dV = 0.0130 m³
so now % change in volume will be
dV % =
× 100
dV % =
× 100
dV % = 2.60 %
so percentage change in volume is 2.60%
and
initial volume v1 =
................3
final volume v2 =
................4
now from equation 3 and 4 , subtract v1 by v2
v2 - v1 =
dV =
put here all value
0.0130 =
dl = 0.004138 m
so water level rise is 4.138 mm
Answer:
Correct option: B. 90%
Explanation:
The confidence interval is given by:
![CI = [\bar{x} - z\sigma_{\bar{x}} , \bar{x}+z\sigma_{\bar{x}} ]](https://tex.z-dn.net/?f=CI%20%3D%20%5B%5Cbar%7Bx%7D%20-%20z%5Csigma_%7B%5Cbar%7Bx%7D%7D%20%2C%20%5Cbar%7Bx%7D%2Bz%5Csigma_%7B%5Cbar%7Bx%7D%7D%20%5D)
If
is 190, we can find the value of
:



Now we need to find the value of
:


So the value of z is 1.71.
Looking at the z-table, the z value that gives a z-score of 1.71 is 0.0436
This value will occur in both sides of the normal curve, so the confidence level is:

The nearest CI in the options is 90%, so the correct option is B.
Answer:
screw is the answer of the question
One way is manager changes itself and the other one is the same thing i think.