Answer:
254.7 g
Explanation:
Hg(ONC)2 -----------> Hg + N2 + 2CO
In every problem of stoichiometry, we must commence with writing the balanced reaction equation as a guide to our calculation. Once we have written the reaction equation, we can now proceed with the solution.
Amount of CO produced= mass of CO produced/ molar mass of CO
Molar mass of CO = 28 gmol-1
Mass of CO produced= 50.2g
Amount of CO produced= 50.2g/28gmol-1
Amount of CO produced= 1.79 moles of CO
From the reaction equation:
1 mole of Hg(ONC)2 produced 2 moles of CO
x moles of Hg(ONC)2 will produce 1.79 moles of CO
x= 1.79 × 1 / 2
x= 0.895 moles of Hg(ONC)2
Molar mass of Hg(ONC)2 = 284.624 g/mol
Mass of Hg(ONC)2 = number of moles × molar mass = 0.895 moles × 284.624 g/mol
Mass of Hg(ONC)2 = 254.7 g
