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3 years ago

A) Balance the equation below.

Chemistry

1 answer:

Advocard [28]3 years ago

3 0

Answer:

254.7 g

Explanation:

Hg(ONC)2 -----------> Hg + N2 + 2CO

In every problem of stoichiometry, we must commence with writing the balanced reaction equation as a guide to our calculation. Once we have written the reaction equation, we can now proceed with the solution.

Amount of CO produced= mass of CO produced/ molar mass of CO

Molar mass of CO = 28 gmol-1

Mass of CO produced= 50.2g

Amount of CO produced= 50.2g/28gmol-1

Amount of CO produced= 1.79 moles of CO

From the reaction equation:

1 mole of Hg(ONC)2 produced 2 moles of CO

x moles of Hg(ONC)2 will produce 1.79 moles of CO

x= 1.79 × 1 / 2

x= 0.895 moles of Hg(ONC)2

Molar mass of Hg(ONC)2 = 284.624 g/mol

Mass of Hg(ONC)2 = number of moles × molar mass = 0.895 moles × 284.624 g/mol

Mass of Hg(ONC)2 = 254.7 g

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