Answer:
Therefore the resistance of the conductor is 175Ω
Explanation:
Resistance:
- Resistance of a metallic conductor is directly proportional to its length(l).
- Resistance of a metallic conductor is inversely proportional to its cross section area(A).
The notation sign of resistance is R.
The unit of resistance is ohm (Ω).
Therefore,
and
ρ is the proportional constant.
It is also known as resistivity of that metal.
Given ρ=35×10⁻⁶Ω-m
l= 20 m
A= 4.0×10⁻⁶m²
=175Ω
Therefore the resistance of the conductor is 175Ω
From that ragged, motley list of statements, only 'C' is true.
Answer:
41.74 m/s
Explanation:
The energy used to draw the bowstring = the kinetic energy of the arrow.
Fd = 1/2mv²................................ Equation 1
Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.
make v the subject of the equation
v = √(2Fd/m)...................... Equation 2
Given: F = 201 N, m = 0.3 kg, d = 1.3 m.
Substitute into equation 2
v = √(2×201×1.3/0.3)
v = √(1742)
v = 41.74 m/s.
Hence the arrow leave the bow with a speed of 41.74 m/s
Answer:
The current lags the potential difference by π/2 in an inductor
Explanation:
The potential difference leads to the current by 
. Alternate signals such as current and voltage -in this case- are periodic, this means that this signals are repeated at fixed spaces of time. Thus, In an inductor the current lags the potential difference by .
Answer:
h f = Wf + K
where the total energy available is h f, Wf is the work function or the work needed to remove the electron and K is the kinetic energy of the removed electron
If K = zero then hf = Wf
Wf = h f = h c / λ or
λ = h c / Wf = 6.63E-34 * 3.0E8 / (3.7 * 1.6E-19)
λ = 6.63 * 3 / (3.7 * 1.6) E-7 = 3.36E-7
This would be 3360 angstroms or 336 millimicrons
Visible light = 400-700 millimicrons
