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Alika [10]
3 years ago
10

Sample Response: Jade's error occurs in the top-right square of the Punnett square. In this square, she identifies the phenotype

as freckles, but to have freckles, the offspring must have at least one dominant allele. The offspring in this box are ff. Because there is no dominant allele present, the offspring will not have freckles.
What did you include in your response? Check all that apply.
Jade’s error occurs in the top-right square of the Punnett square.
Jade identifies the phenotype as freckles.
To have freckles, the offspring must have at least one dominant allele.
The offspring in this box are ff.
There is no dominant allele present, so the offspring will not have freckles.
Chemistry
1 answer:
Anettt [7]3 years ago
4 0

Answer:

all of them

Explanation:

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In order to determine the magnetic properties of phosphorus atom we need to find out the number of unpaired electrons present in
Papessa [141]

Answer:

Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer

Explanation:

Hope this helps :)

7 0
2 years ago
Carbon-12 contains 6 protons and 6 neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of t
Slav-nsk [51]

Explanation:

Let us assume that volumes is equal to spheres  volume of nucleus.

fm = femto meter = 10^{-15}

pm = pico meter = 10^{-12}

Hence, calculate the volume as follows.

          V = \frac{4}{3} \times \pi \times r^{3}

              = \frac{4}{3} \times 3.14 \times (2.7)^{3}

              = 82.4481 fm^{3} (cubic femtometers)

or,          = 82 fm^{3}

Now, we will calculate the volume of the atom as follows.

          V = \frac{4}{3} \times \pi \times r^{3}

             = \frac{4}{3} \times 3.14 \times (70)^{3}

             = 1436758.4 pm^{3} (cubic picometers)

thus, we can conclude that volume of the nucleus is 82 fm^{3}  and volume of the atom is 1436758.4 pm^{3}.

7 0
3 years ago
2. Choose the atom from each of the following pairs with the greater ionization energy: a. Be and Ba b. Al and Ar c. Ca and Cl
beks73 [17]

Considering the definition of ionization energy, the highest ionization energy belongs to the element:

a. Be

b. Ar

c. Cl

Electrons are held in atoms by their attraction to the nucleus, which means that energy is needed to remove an electron from the atom.

You should keep in mind that the electrons of the last layer are always lost, because they are the weakest attracted to the nucleus.

Ionization energy, also called ionization potential, is the necessary energy that must be supplied to a neutral, gaseous, ground-state atom to remove an electron from an atom. When an electron is removed from a neutral atom, a cation with a charge equal to +1 is formed.

In a group, the ionization energy increases upwards because when passing from one element to the bottom, it contains one more layer of electrons. Therefore, the valence layer electrons, being further away from the nucleus, will be less attracted to it and it will cost less energy to pluck them.

In the same period, in general, it increases as you shift to the right. This is because the elements in this way have a tendency to gain electrons and therefore it will cost much more to tear them off than those on the left which, having few electrons in the last layer will cost them much less to lose them.

Considering all the above, from each of the pairs, the highest ionization energy belongs to the element:

a. Be

b. Ar

c. Cl

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6 0
2 years ago
Why k has more shielding effect than Na?​
lara [203]

Explanation:

As the charge of all electrons are equal, the repulsive force exerted by each of them is also going to be equal. So, as K has more electrons repulsing its valence electron than Na, it has greater electron shielding.

8 0
3 years ago
55. Which Element has a larger radius- Rb or I?
Luden [163]

Rb has larger radius.

5 0
3 years ago
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