I think the correct answer from the choices listed above is the second option. If a copper atom loses two electrons, the name of the copper ion is copper (II) ion . Also it is called cupric acid. However, the latter <span>is an old term and is not recommended. Hope this answers the question.</span>
Answer:
CH₃CH₂CH₂CH₂CH₂OH - E. Alcohol
CH₃CH₂OCH₂CH₃ - F. ether
CH₃CH₂CH₂SH - G. thiol
CH₃COOH - J. Carboxylic acid
CH₃CH(OH)CH₂CH₃ - E. Alcohol
CH₃CH₂CH₂CH₂CHO - A. Aldehyde
CH₃CH₂CH₂COCH₃ - B. Ketone
Explanation:
Currently taking organic chemistry.
Hope this helps. :)
Answer:
with 7 valence electrons.
Explanation:
Bromine has 7 unpaired (valence) electrons in its outer shell, and a total of 35 elecrons. Its <em>4s</em> orbital is completely filled with 2 electrons.
The closest answer from the options would be option D.
I hope this helps.
Answer:
Explanation:
M(s) → M (g ) + 20.1 kJ --- ( 1 )
X₂ ( g ) → 2X (g ) + 327.3 kJ ---- ( 2 )
M( s) + 2 X₂(g) → M X₄ (g ) - 98.7 kJ ----- ( 3 )
( 3 ) - 2 x ( 2 ) - ( 1 )
M( s) + 2 X₂(g) - 2 X₂ ( g ) - M(s) → M X₄ (g ) - 98.7 kJ - 2 [ 2X (g ) + 327.3 kJ ] - M (g ) - 20.1 kJ
0 = M X₄ (g ) - 4 X (g ) - M (g ) - 773.4 kJ
4 X (g ) + M (g ) = M X₄ (g ) - 773.4kJ
heat of formation of M X₄ (g ) is - 773.4 kJ
Bond energy of one M - X bond = 773.4 / 4 = 193.4 kJ / mole
