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2 years ago

Please Help!! What is the measure of angle AXB?

Mathematics

2 answers:

Goshia [24]2 years ago

4 0

Answer:

Step-by-step explanation:

Two angles are supplementary when their sum is 180

∠AXB + ∠BXC = 180° {Supplementary angles}

8x + 10 + 2x - 20 = 180

Add the like terms

10x - 10 = 180

10x = 180 + 10

10x = 190

x = 190/10

x = 19°

∠AXB = 8x + 10

= 8 * 19 +10

= 152 + 10

∠AXB = 162

Firlakuza [10]2 years ago

3 0

Answer:

180 degrees

Step-by-step explanation: the measure of angle AXB is ( a + a ) and the sum of the measured angles AXB and BXC = 180 , so a + ( a + a) = 180.

both these angles add up to be 180 degrees because they are both supplementary angles they both share the sides of x and b.

if it confuses you, just use a bit of repeated addition and multiplication

for example : 30 + 30 + 30 + 30 + 30 = 5 x 30 which equals to 150

because you add 30 , 5 times .

You might be interested in

What is the domain of the function s=-4r^2 if the range is s <_ 0

vlada-n [284]

Answer:

r≤0

Step-by-step explanation:

if the range is s≤0, (that means the value of s is all negative integers &0) to find the domain we have to replace that some negative integers &0.

we can replace some values of s as the following

s=‒4(0)^2 s=‒4(‒1)^2

=‒4(0) =‒4(1)

=0 =‒4

s=‒4(‒2)^2 s=‒4(‒3)^2

=‒4(4) =‒4(9)

=‒16 =‒36

so we can understand easly that the domain is negative integer&0,it can't be positive because the square of any integer is positive.

therefore the answer is r≤0

i think &i hope it is clear.

3 0

2 years ago

132=-6+3(1-5p) solve the equation

photoshop1234 [79]

Answer:

p=-9

Step-by-step explanation:

132=-6+3 (1-5p)

-6+3 (1-5p)=132

-6+3 (1-5p)+6=132+6

3(1-5p)=138

3(1-5p)/3=138/3

1-5p=46

1-5p-1=46-1

-5p=45

p=-9

5 0

2 years ago

Read 2 more answers

A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe

djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

$\mathbf{h(t) = -16t^2 + 160t}$

Differentiate the function with respect to t

$\mathbf{h'(t) = -32t + 160}$

Set to 0

$\mathbf{h'(t) = -32t + 160 = 0}$

So, we have:

$\mathbf{-32t + 160 = 0}$

Collect like terms

$\mathbf{-32t =- 160 + 0}$

$\mathbf{-32t =- 160}$

Solve for t

$\mathbf{t = \frac{- 160}{-32}}$

$\mathbf{t = 5}$

Hence, the projectile reaches the maximum after 5 seconds