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alexandr402 [8]
3 years ago
10

What causes light to bend when it moves from one transport medium to another

Physics
1 answer:
faltersainse [42]3 years ago
5 0

Answer:

The bending of light as it passes from one medium to another is called refraction. The angle and wavelength at which the light enters a substance and the density of that substance determine how much the light is refracted. The bending occurs because light travels more slowly in a denser medium.

hope this helped :))

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3. How did Kepler's work influence Newton?
Katarina [22]

Johannes Kepler and his laws were a great influence on Isaac Newton. ... Newton used his laws of gravity and motion to derive Kepler's laws and show that the motion of the planets could be explained using mathematics and physics.

3 0
3 years ago
Read 2 more answers
in terms of mechanical advantage and velocity ratio write an expression for the efficiency of a simple machine​
mixer [17]

Answer:

Efficiency = (MA/VR) ×100%

8 0
3 years ago
A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part
Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

(I_p)s = \frac{\pi(0.55)4}2

      = 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

T_{max} = T_{allow} \frac{I_p}{r}

         =(14 \times 10^3) \times (\frac{0.14374}{0.55})

         = 3658.836 lb.in

         = \frac{3658.836}{12} lb.ft

        = 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

T_{max} = T_{allow}( \frac{Ip}{r})

          = (14 \times10^3) \times ( \frac{0.13101}{0.55})

          = 3334.8 lb.in

          = (\frac{3334.8}{12} ) lb.ft

          = 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

P_{max} = 2 \pi f_T

          = 2\pi(2.1) \times 304.9

          = 4023.061 lb. ft/s

          = (\frac{4023.061}{550}) hp

          = 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

P _{max,t} = 2\pi f_T

            = 2\pi(2.1) \times 277.9

            = 3666.804 lb.ft /s

            = (\frac{3666.804}{550})hp

            = 6.667 hp

7 0
3 years ago
015 10.0 points
Salsk061 [2.6K]

Answer:

20.996 m

Explanation:

Given:

Initial velocity, u=0 \textrm{ m/s}

Final velocity, v=12.4062 \textrm{ m/s}

Total time taken, t_{Total} = 7.13 s.

∴ Acceleration is given as,

a=\frac{v-u}{t_{Total}}=\frac{12.4062-0}{7.13}=1.74 m/s²

Now, using Newton's equation of motion, we find the displacement.

Displacement is given as:

s=ut+\frac{1}{2} at^{2}

Plug in 0 for u, 4.91257 for t and 1.74 for a. Solve for s.

This gives,

s=0+\frac{1}{2} \times 1.74 \times (4.91257)^{2}=20.996 \textrm{ m}

Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.

7 0
3 years ago
A cyclist traveling at 30.0m/s along a straight road comes uniformly to stop in 5.00s. Determine the stopping acceleration, the
Amiraneli [1.4K]

Answer:

I. Stopping acceleration = 6 m/s²

II. Stopping distance, S = 75 meters

Explanation:

Given the following data;

Final velocity = 30 m/s

Time = 5 seconds

To find the stopping acceleration;

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation;

a = \frac{30 -  0}{5}

a = \frac{30}{5}

Acceleration = 6 m/s²

II. To find the stopping distance, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

30² = 0² + 2*6*S

900 = 12S

S = 900/12

S = 75 meters

7 0
3 years ago
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