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Sati [7]
3 years ago
15

What is necessary to designate a position? A. a reference point B. a direction C. fundamental units D. motion E. all of these

Physics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

E. all of these

Explanation:

The designation of a point in space all the points that necessary

- reference point

- a direction

- fundamental units

- a direction

- motion

all are necessary to designate a point in space. Hence option E is correct.

For example in simple harmonic motion we need to specify all the above factors of the object in order to designate the position of the object.  

You might be interested in
Under which circumstances would protesters’ right to assembly most likely be protected?
ICE Princess25 [194]

Answer:

Explanation:

Mob violence is never protected. Organizers are always careful about not letting things get out of hand. Not D

That remark sort of applies to C as well. Property destruction is never protected.

B is something assemblies are allowed to do. So B.

A falls into the same category as C and D. You may not like the fact that he/she is doing something illegal, but you can't take away their privacy.

7 0
3 years ago
A student sits on a rotating stool holding two 3.09-kg masses. When his arms are extended horizontally, the masses are 1.08 m fr
schepotkina [342]

Answer:

a

The New angular speed is  w_f = 2.034 rad/s

b

The Kinetic energy before the masses are pulled in is  KE_i = 3.101 \ J

c

The Kinetic energy after the masses are pulled in is   KE_f = 8.192 \ J

Explanation:

From the we are told that masses are 1.08 m from the axis of rotation, this means that

             The radius r =1.08m

              The  mass is m = 3.09\  kg

              The  angular speed w = 0.770 \ rad/sec

  The moment of inertia of the system excluding the two mass I = 3.25 \ kg \cdot m^2

           New radius  r_{new} = 0.34m

             

Generally the conservation of angular momentum can be mathematical represented as

                         w_f = [\frac{I_i}{I_f} ]w_i .....(1)

Where w_f is the final angular speed

           w_i is the initial  angular speed

          I_i is the initial moment of inertia

           I_f is the final moment of inertia

Moment of inertia is mathematically represented as

                       I = m r^2

Where I is the moment of inertia

          m is the mass

           r is the radius

So the Initial moment of inertia is given as  

     I_i = moment \ of \  inertia \ of\  the  \ two \  mass \ + 3.25 \ kg \cdot m^2

     I_i = 2m r^2 + 3.25

The multiplication by is because we are considering two masses

    I_i = 2 [(3.09)(1.08)^2] +3.25 = 10.46 kg \cdot m^2

So the final  moment of inertia is given as  

     I_f = 2[(3.09)(0.34)^2] +3.25 = 3.96 \ kg \cdot m^2      

Substituting these values into equation 1

         w_f = [\frac{10.46}{3.96} ] * 0.77 = 2.034 \ rad/sec                                                          

Generally Kinetic energy is mathematically represented in term of moment of inertia as

                       KE = \frac{1}{2} * I * w^2

Now considering the kinetic energy before the masses are pulled in,

                     KE_i = \frac{1}{2} * I_i * w^2_i

The Moment of inertia would be  I_i = 10.46 \ Kg \cdot m^2

  The Angular speed would be  w_i = 0.77 \ rad/s

Now substituting these value into the equation above

              KE_i = \frac{1}{2} * (10.46) * (0.770)^2 = 3.101 J

Now considering the kinetic energy after the masses are pulled in,                      

               KE_f = \frac{1}{2} * I_f * w^2_f

The Moment of inertia would be  I_f = 3.96 \ Kg \cdot m^2

The Angular speed would be  w_f = 2.034 \ rad/s

Now substituting these value into the equation above

                        KE_f= \frac{1}{2} *(3.96)(2.034)^2  

                        = 8.192J        

8 0
3 years ago
You have two electrical devices plugged into the same socket in parallel and draws 120 V. The first device has a resistance of 2
erik [133]

The devices don't "draw" 120v. The 120v comes to your house from the power company. They decide it should be 120v and that's what they send you. It's hypothetically technically possible for you to change that, but if you try it, you'll definitely burn the house down.

The total resistance of those two devices in parallel is 6 and 2/3 ohms. That doesn't depend on what they're plugged into. It would still be 6 and 2/3 ohms if they were connected in parallel, wrapped in tissue, sealed in a jar of chicken soup and stored in a box on a high shelf.

But since they ARE plugged into 120v, they draw 18 Amperes from the socket, and they turn all of that electrical energy into 2160 watts of heat. That's about the same as a good size toaster oven, and you have to figure out a way to get rid of all that heat before you burn the house down.

4 0
3 years ago
Upon reaching a velocity of 100fps, the pilot of the airplane decides to abort the take off and applies brakes and stops the air
masha68 [24]

Answer:

5 ft/s²

Explanation:

u = Initial velocity = 100 ft/s

v = Final velocity = 0

s = Displacement = 1000 ft

a = Acceleration

From equation of motion

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-100^2}{2\times 1000}\\\Rightarrow a=-5\ ft/s^2

1\ ft/s^2=0.3048\ m/s^2\\\Rightarrow 5\ ft/s^2=5\times 0.3048\ m/s^2=1.524\ m/s^2

The airplane's deceleration is 5 ft/s² or 1.524 m/s²

8 0
3 years ago
1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa
WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

W= mg

m = \dfrac{W}{g}

Put the value into the formula

m=\dfrac{81.34}{9.8}

m=8.3\ kg

The mass per unit length of the wire

m_{l}=\dfrac{m}{l}

Put the value into the formula

m_{l}=\dfrac{8.3}{10000}

m_{l}=8.3\times10^{-4}\ kg/m

We need to calculate the frequency in the wire

Using formula of frequency

f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}

Put the value into the formula

f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}

f_{w}=189.62\ Hz

We need to calculate the beat frequency

Using formula of beat frequency

f_{b}=f_{in}-f_{w}

Put the value into the formula

f_{b}=196-189.622

f_{b}=6.378\ Hz

Hence, The beat frequency is 6.378 Hz.

5 0
3 years ago
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