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3 years ago

Match the speed to the section that describes.

Physics

1 answer:

inn [45]3 years ago

4 0

Answer:

a=2 ok do it and ........

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Two objects are attracted to each other by electromagnetic forces. Suppose I double the charge of one object. How can I return t

nata0808 [166]

Answer:

1. Reduce the charge on second object by half or

2. Increase the distance between the two charges by a factor of 1.41 (√2).

Explanation:

Lets assume,

Charge on first object = Q

Charge on second object = q

Distance between them = r

Force between the two charges = F

According to Coulomb's law,

$F = k \frac{Qq}{r^{2}}$

where, k = Coulomb constant

New value of charge on first object = 2Q. Thus the new force(F') will be

$F' = k \frac{2Qq}{r^{2}}$

$F' = 2F$

So, to bring the value of force(F') to original value, there are two options:

1. Reduce the charge on second object by half or

2. Increase the distance between the two charges by a factor of 1.41 (√2).

4 0

3 years ago

If a capital letter R is seen in an ordinary mirror , what does it look like?

Radda [10]

Answer:

........................

7 0

2 years ago

Read 2 more answers

Potential energy is energy due to the:

kykrilka [37]

Answer:I will say d

Explanation: because Potential energy is the energy stored within an object, due to the object's position, arrangement or state. Potential energy is one of the two main forms of energy, along with kinetic energy.

6 0

3 years ago

A baseball with a mass of 0.15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8.

Vedmedyk [2.9K]

Answer: 1687.5 N

Explanation:

From the second law of motion given by Newton, Force is the rate change of momentum.

$F = \frac{dp}{dt}=\frac {m dv}{dt} = \frac{m (v_f-v_i)}{dt}$

Mass of the baseball, m = 0.15 kg

Initial velocity, $v_i=-40 m/s$ (negative because direction of initial velocity is opposite to the final velocity)

Final velocity, $v_f=50 m/s$

The duration of collision, $dt= 8.0 \times 10^{-3} s$

Force, $F = \frac{0.15 kg (50-(-40) m/s)}{8.0 \times 10^{-3} s}=1687.5 N$

Hence, the value of force is 1687.5 N.

8 0

3 years ago

If the cross-section of a wire of fixed length is doubled, how does the resistance of that wire change? A. Halved. B. Doubled C.

Vinil7 [7]

(B)It would get doubled.

7 0

3 years ago