Answer:
a)
, b) ![v \approx 7745.967\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%5Capprox%207745.967%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
a) The potential energy is:
![U_{e} = Q \cdot \Delta V](https://tex.z-dn.net/?f=U_%7Be%7D%20%3D%20Q%20%5Ccdot%20%5CDelta%20V)
![U_{e} = (30\,C)\cdot (1.0\times 10^{9}\,V)](https://tex.z-dn.net/?f=U_%7Be%7D%20%3D%20%2830%5C%2CC%29%5Ccdot%20%281.0%5Ctimes%2010%5E%7B9%7D%5C%2CV%29)
![U_{e} = 3 \times 10^{10}\,J](https://tex.z-dn.net/?f=U_%7Be%7D%20%3D%203%20%5Ctimes%2010%5E%7B10%7D%5C%2CJ)
b) Maximum final speed:
![U_{e} = \frac{1}{2}\cdot m \cdot v^{2}\\v = \sqrt{\frac{2\cdot U_{e}}{m} }](https://tex.z-dn.net/?f=U_%7Be%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%20%5Ccdot%20v%5E%7B2%7D%5C%5Cv%20%3D%20%5Csqrt%7B%5Cfrac%7B2%5Ccdot%20U_%7Be%7D%7D%7Bm%7D%20%7D)
The final speed is:
![v=\sqrt{\frac{2\cdot (3 \times 10^{10}\,J)}{1000\,kg} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2%5Ccdot%20%283%20%5Ctimes%2010%5E%7B10%7D%5C%2CJ%29%7D%7B1000%5C%2Ckg%7D%20%7D)
![v \approx 7745.967\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%5Capprox%207745.967%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Answer:
Option (C)
Explanation:
The nuclear energy is defined as a type of energy which liberates either by the process of nuclear fusion or nuclear fission and is mainly used to generate electricity. This energy is stored in the core of an atom (or nucleus).
It is highly effective, cost-effective and there is no emission of greenhouse gases.
But it also has some disadvantages, of which one is that it produces radioactive waste materials, which are difficult to dispose these substances and is also a very expensive method. These materials emit radiations that are harmful to the organisms. So, it is very challenging to dispose these radioactive waste materials.
Thus, the correct answer is option (C).
Answer:
0.911 atm
Explanation:
In this problem, there is no change in volume of the gas, since the container is sealed.
Therefore, we can apply Gay-Lussac's law, which states that:
"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"
Mathematically:
![p\propto T](https://tex.z-dn.net/?f=p%5Cpropto%20T)
where
p is the gas pressure
T is the absolute temperature
For a gas undergoing a transformation, the law can be rewritten as:
![\frac{p_1}{T_1}=\frac{p_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_1%7D%7BT_1%7D%3D%5Cfrac%7Bp_2%7D%7BT_2%7D)
where in this problem:
is the initial pressure of the gas
is the initial absolute temperature of the gas
is the final temperature of the gas
Solving for p2, we find the final pressure of the gas:
![p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm](https://tex.z-dn.net/?f=p_2%3D%5Cfrac%7Bp_1%20T_2%7D%7BT_1%7D%3D%5Cfrac%7B%280.981%29%28314%29%7D%7B338%7D%3D0.911%20atm)
5.16 meters!!!!!!!!!!!!!!!!!!!!