Answer:
Minimum Allowable diameter for each of the 5 bolts = 0.0394 m = 3.94 cm
Explanation:
Maximum Working Stress = Ultimate Shear Stress/factor of safety
Maximum Working Stress = 280 MPa/3.8 = 73.68 MPa
Working Stress = Applied load/Minimum allowable Area = L/A
Minimum Allowable Area = Applied Load/Maximum Working Stress
A = 450000/73680000 = 0.00611 m²
This area is supplied by 5 bolts, so each bolt supplies A/5 = 0.0061/5 = 0.00122 m²
Cross sectional Area of bolts = πD²/4
0.00122 = πD²/4
D² = 4 × 0.00122/π = 0.00155
D = √0.00155 = 0.0394 m = 3.94 cm
Each of the five bolt can have a minimum diameter of 3.94 cm
Hope this Helps!!!
Depends on your defense and probably
Answer:
point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))
Explanation:
The distance formula is the difference of the x coordinates squared, plus the difference of the y coordinates squared, all square rooted. For the general case, it appears you simply need to change how you have written the code.
point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))
Note, by moving the 2 inside of the pow function, you have provided the second argument that it is requesting.
You were close with your initial attempt, you just had a parenthesis after x1 and y1 when you should not have.
Cheers.
Answer:
Explanation:
Initial conditions
Final conditions
Steady flow energy equation
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![\dot{m}c_p\left [ T_1-T_2\right ]+\left [ -5hp\right ]=\dot{W} -5\times 746\times 3.4121](https://tex.z-dn.net/?f=%5Cdot%7Bm%7Dc_p%5Cleft%20%5B%20T_1-T_2%5Cright%20%5D%2B%5Cleft%20%5B%20-5hp%5Cright%20%5D%3D%5Cdot%7BW%7D%20-5%5Ctimes%20746%5Ctimes%203.4121)
![-4\dot{m}-\dot{m}\times 0.24\times \left [ 400-60\right ]](https://tex.z-dn.net/?f=-4%5Cdot%7Bm%7D-%5Cdot%7Bm%7D%5Ctimes%200.24%5Ctimes%20%5Cleft%20%5B%20400-60%5Cright%20%5D)
