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dmitriy555 [2]
2 years ago
13

Reason fo I.EE regulations in electrical installations​

Engineering
1 answer:
klasskru [66]2 years ago
7 0

Answer:

The IEE Wiring Regulations Explained and Illustrated, Second Edition discusses the recommendations of the IEE Regulations for the Electrical Equipment of Buildings for the safe selection or erection of wiring installations. The book emphasizes earthing, bonding, protection, and circuit design of electrical wirings.

Explanation:

i hope it help you please make me brainlist and answer my question

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The tank shown in the accompanying figure is being filled by pipes 1 and 2. If the water level is to remain constant, what is th
VMariaS [17]

Answer: 2.93 ft/sec

Explanation:  Calculate the volume/sec entering from the two inlets (Pipes 1 and 2), add them, and then calculate the flow in Pipe 3.

The table illustrates the approach.  I calculated the volume of each pipe for a 1 foot section with the indicated diameters, divided by 2 for the radius of each  using  V = πr²h.  Units of V are in^3/foot length.  Now we can multiply that volume by the flow rate, in ft/sec, to obtain the flow rate in in^3/sec.  

Add the two rates from Pipes 1 and 2 (62.14 in^3/sec) to arrive at the flow rate for Pipe 3 necessary to keep the water level constant.  Calculate the volume of 1 foot of Pipe 3 (21.21 in^3/foot) and then divide this into the inflow sum of 62.14 in^3/sec to find the flow rate of Pipe 3 (in feet/sec) necessary to keep the water level constant.

That is 2.93 ft/sec.

6 0
3 years ago
An ideal gas turbine operates using air coming at 355C and 350 kPa at a flow rate of 2.0 kg/s. Find the rate work output
GuDViN [60]

Answer:

The rate of work output = -396.17 kJ/s

Explanation:

Here we have the given parameters

Initial temperature, T₁ = 355°C = 628.15 K

Initial pressure, P₁ = 350 kPa

h₁ = 763.088 kJ/kg

s₁ = 4.287 kJ/(kg·K)

Assuming an isentropic system, from tables, we look for the saturation temperature of saturated air at 4.287 kJ/(kg·K) which is approximately

h₂ = 79.572 kJ/kg

The saturation temperature at the given

T₂ = 79°C

The rate of work output \dot W = \dot m×c_p×(T₂ - T₁)

Where;

c_p = The specific heat of air at constant pressure = 0.7177 kJ/(kg·K)

\dot m =  The mass flow rate = 2.0 kg/s

Substituting the values, we have;

\dot W = 2.0 × 0.7177 × (79 - 355) = -396.17 kJ/s

\dot W = -396.17 kJ/s

7 0
4 years ago
Project 8:The Harris-Benedict equation estimates the number of calories your body needs to maintain your weight if you do no exe
lilavasa [31]

Answer:

See explaination and attachment for the program code and output

Explanation:

#include <iostream>

using namespace std;

int main()

{

char gender; //details for gender and checking

char ans;

do

{

cout<<"Gender (M or F): ";

cin>>gender;

switch(gender)

{

case 'M':

//cout<<"Male."<<endl;

break;

case 'F':

//cout<<"Female."<<endl;

break;

default:

cout<<"Wrong Gender. Please enter again (M or F): ";

cin>>gender;

}

int Weight,Height,Age; //declaration of variables

double bmr;

cout<<"Weight: ";

cin>>Weight;

cout<<"Height (in inches): ";

cin>>Height;

cout<<"Age: ";

cin>>Age;

//bmr calculations for male and female

if (gender = 'M')

{

bmr = 66 + (6.3 * Weight) + (12.9 * Height) - (6.8 * Age);

cout<<"He needs "<<bmr<<" to maintain his weight."<<endl;

cout<<"He needs to eat "<<(bmr/230)<< " candy bars in one day."<<endl;

}

else if (gender = 'F')

{

bmr = 655 + (4.3 * Weight) + (4.7 * Height) - (4.7 *Age);

cout<<"She needs "<<bmr<<" to maintain her weight"<<endl;

cout<<"She needs to eat "<<(bmr/230)<< " candy bars in one day."<<endl;

}

cout<< "Do you want to do another one>continue (Y/N): ";

cin >> ans;

}while(ans=='y'||ans=='Y');

cout<<"\n Thanks for using my BMR calculator. Good Bye!.";

return 0;

}

Kindly check attachment for output.

4 0
3 years ago
Please view the file attached below and help me answer all the questions!!
evablogger [386]

Answe whats the question i can help you

Explanation:

8 0
3 years ago
Two very long concentric cylinders of diameters D1 = 0.42 m and D2 = 0.5 m are maintained at uniform temperatures of T1 = 950 K
MrRa [10]

Answer:

Q=33.34 KW/m

Explanation:

Given that

D₁=0.42 m

A₁= π D₁ L

For unit length

A₁= π D₁ = 0.42 π m²

D₂=0.5 m

A₂= 0.5 π m²

ε₁= 1 ,ε₂= 0.55

T₁=950 K  ,T₂ = 500 K

Q=\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{A_1\epsilon _1}+\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+\dfrac{1}{A_1F_{12}}}

F₁₁+F₁₂= 1

F₁₁= 0

So, F₁₂= 1

Q=A_1\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{\epsilon _1}+A_1\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+1}

Q=0.42\pi \dfrac{5.67\times 10^{-8}(950^4-500^4)}{\dfrac{1-1}{1}+0.42\pi\times \dfrac{1-0.55}{0.5\pi\times 0.55}+1}

Q=33.34 KW/m

3 0
4 years ago
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