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2 years ago

Driving Distraction Brainstorming Session

1 answer:

5 0

texting, phone calls, putting on makeup, brushing hair, movies playing in car, loud music, children, and that's pretty much all I could think of

please give BRAINLIEST ANSWER └[T‸T]┘

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A force is a push or pull in? A.a circle B.an arc C.a straight line

Salsk061 [2.6K]

Answer:

I think it is B: an arc

Explanation:

Hope this helps. Mark as brainiest

8 0

2 years ago

(1) Estimate the specific volume in cm3 /g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the virial equation and compa

ludmilkaskok [199]

Answer:

70.66 cm^3

The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )

Explanation:

Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----

Viral equation can also be rewritten as :

Z = 1 + B ( P/RT )

B ( function of time )

Temperature = 310 K

P1 = 8 bar

P2 = 75 bar

Determine the specific volume in cm^3

V = 70.66 cm^3

b) comparing the specific volumes to the experimental values

70.58 and 3.90

The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )

attached below is the detailed solution

3 0

2 years ago

A Michelson interferometer operating at a 500 nm wavelength has a 3.73-cm-long glass cell in one arm. To begin, the air is pumpe

LekaFEV [45]

Answer:

The number of bright-dark fringe is 42

Solution:

As per the question:

Wavelength of light, $\lambda = 500\ nm = 500\times 10^{- 9}\ m$

Length of the glass cell, x = 3.73 cm = 0.0373 m

Refractive index, $\mu = 1.00028$

Now,

To calculate the bright-dark fringe shifts, we use the formula given below:

$d_{m} = \frac{2x}{\lambda }\times (\mu - 1)$

Now, substituting the appropriate values in the above formula:

$d_{m} = \frac{2\times 0.0373}{500\times 10^{- 9}}\times (1.00028 - 1)$

$d_{m} = 41.77$ ≈ 42

6 0

3 years ago

Technician A says when the brakes are applied in a vacuum booster, the vacuum control valve is closed. Technician B says the vac

Wewaii [24]

Answer:

Technician A only

Explanation:

The application of the breaks by stepping on the break pedal moves the pedal pushrod and plunger forward within the diaphragm plate, bringing about the contact between the vacuum port seal and the vacuum valve that closes the vacuum port and the passage that connects the left and right chambers such that the pressure in one chamber and te vacuum in the other chamber are held steady.

4 0

2 years ago

Which two is right about febuary 14

igor_vitrenko [27]

Answer:A and B

Explanation:

3 0

3 years ago

Read 2 more answers