Answer:
First one is probably B
Second one is False
Third one is True
Explanation:
Every workplace or school is different so I'm not really sure.
Answer:
A computer programmer, sometimes called a software developer, a programmer or more recently a coder (especially in more informal contexts), is a person who creates computer software.
Answer:
the data are inadequate
Explanation:
<u>If there are 15 people on the team, and only five have been asked about the mascot, </u><u>this means the data collecting is wrong, and the result doesn’t include thoughts of the majority</u>. If Diana and Kinsey want to have adequate data,<u> they should ask as many as possible, if not all players in the team</u>. This would truly show what the majority wants meaning it will show what the team wants. This kind of complete data correcting is the correct one.
Answer:
Place the jack under the part of the vehicle that it should contact when raised. If you're using jack stands, place them near the jack. If you place your jack incorrectly, you can injure your car. To find the proper place to position the jack for your particular vehicle, check your owner's manual.
Complete question:
A rod consisting of two cylindrical portions AB and BC is restrained at both ends. Portion AB is made of steel (Es = 200 GPa and αs = 11.7 × 10-6/°C) and portion BC is made of brass (Eb = 105 GPa and αb = 20.9 × 10-6/°C). (diameter of AB is 30mm, Length of AB is 250 mm) and (diameter of BC is 50mm, Length of BC is 300 mm).
Knowing that the rod is initially unstressed, determine the compressive force induced in ABC when there is a temperature rise of 55°C
Answer:
The compressive force induced in ABC is 156.902 kN
Explanation:
Area of portion AB:
= 7.0695 X 10⁻⁴ m²
Area of portion BC:
= 1.96373 X 10⁻³ m²
Free thermal expansion:
= (0.25)(11.7 X 10⁻⁶)(55) + (0.3)(20.9 X 10⁻⁶)(55)
= 505.725 X 10⁻⁶m
Shortening due to induced compressive force P:


= 1.7682 X 10⁻⁹P + 1.455 10⁻⁹P
= 3.2232 X 10⁻⁹P
For zero net deflection, 
∴ 3.2232 X 10⁻⁹P = 505.725 X 10⁻⁶
P = 156.902 X 10³ N = 156.902 kN
Therefore, the compressive force induced in ABC is 156.902 kN