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Bogdan [553]
3 years ago
10

What do you think of the category of polymer for making a helmet?​

Engineering
2 answers:
Mice21 [21]3 years ago
8 0

Answer: Find the answer in the explanation

Explanation:

Helmets are manufactured by the use of different categories of polymer. The common material used for manufacturing of helmets are:

1. Polycarbonate

2. Styrofoam

3. Foam

4. Acrylic and polycarbonate

5. Nylon

All the polymer used for the manufacturing of helmets fall under synthetic and semi synthetic categories of polymer.

The styrofoam is classified under addition polymerization. While the nylon is classified under condensation polymerization.

The low density polythene used is classified as branch chains polymer. While the polycarbonate is of high tensile strength with strong mechanical properties.

jarptica [38.1K]3 years ago
3 0
I think that is a very good idea

;)
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Semmy [17]

Answer: Your question has some missing figures so kindly plug in the values into the solution provided to get the exact amount of money saved

answer : Electric power generated = 216 * 10^6 kJ

             money saved = $0.XY * 60000 kwh

Explanation:

<u>Calculating  the amount of electric power generated by wind turbine</u>

power generated = ( 30 * 2000 ) kWh  = 60000 kWh

Electric energy generated = 60000 kWh * 3600 kJ = 216 * 10^6 kJ

<u>Calculate money saved by school per year </u>

$0.XY * 60000 kwh

5 0
2 years ago
1. Band saw lower wheel does not require a guard * true or false 2. Band saw upper guide should be adjusted to within 1/8" of th
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Answer:

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2 years ago
What is the hardest part of engineering?
Vikki [24]

ANSWER:

Aerospace Engineering. ...

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7 0
1 year ago
What is stress corrosion cracking?
aksik [14]

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6 0
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Windmills slow the air and cause it to fill a larger channel as it passes through the blades. Consider a circular windmill with
Scilla [17]

Answer:

DIAMETER  = 9.797 m

POWER = \dot W = 28.6 kW

Explanation:

Given data:

circular windmill diamter D1 = 8m

v1 = 12 m/s

wind speed = 8 m/s

we know that specific volume is given as

v =\frac{RT}{P}

  where v is specific volume of air

considering air pressure is 100 kPa and temperature 20 degree celcius

v =  \frac{0.287\times 293}{100}

v = 0.8409 m^3/ kg

from continuity equation

A_1 V_1 = A_2 V_2

\frac{\pi}{4}D_1^2 V_1 = \frac{\pi}{4}D_1^2 V_2

D_2 = D_1 \sqrt{\frac{V_1}{V_2}}

D_2 = 8 \times \sqrt{\frac{12}{8}}

D_2 = 9.797 m

mass flow rate is given as

\dot m = \frac{A_1 V_1}{v} = \frac{\pi 8^2\times 12}{4\times 0.8049}

\dot m = 717.309 kg/s

the power produced \dot W = \dot m \frac{ V_1^2 - V_2^2}{2} = 717.3009 [\frac{12^2 - 8^2}{2} \times \frac{1 kJ/kg}{1000 m^2/s^2}]

\dot W = 28.6 kW

8 0
3 years ago
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