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kumpel [21]
3 years ago
13

Which type of elevated stand does not need a tree?

Engineering
1 answer:
SashulF [63]3 years ago
4 0

Answer:

Elevated stands place the hunter above ground level. They can be tree stands placed in or against trees, or freestanding structures. They have become increasingly popular in recent years with both firearm and bow hunters.

Explanation:

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Dowry practice is considered to be a social problem . justify<br>​
Artemon [7]

Answer:

mark me brailinist

Explanation:

Dowry is a social evil in the society, that has caused unimaginable tortures and crimes towards women. The evil has taken lives of women from all stratas of society - be it poor, middle class or the rich. However it is the poor who succumb and fall prey to it, more due to their lack of awareness and education.

It is because of the dowry system, that daughters are not valued as much as the sons. In the society, many a times it has been seen that they are seen as a liability and are often subjected to subjugation and are given second hand treatment may it be in education or other amenities.

Today the government has come up with many laws and reforms, not only to eradicate the dowry system, but also to uplift the status of the girl child by bringing in many schemes.

It is now for the society at large to become aware and understand the situation. It up to all of us to take active steps in bringing about the necessary change and stop either giving or taking dowry. We must all know that we should start valuing our daughters first, so that others know their value once they grow up.

7 0
2 years ago
In the LC-3 data path, the output of the address adder goes to both the MARMUX and the PCMUX, potentially causing two very diffe
dangina [55]

Answer:

no need for that

Explanation:

they are not the same at all

3 0
3 years ago
The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
Aliun [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1

The Lower Surface Cp is given as

Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

The difference of the Cp over the airfoil is given as

\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

Now the coefficient of moment about the leading edge is given as

C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

5 0
3 years ago
Time management is a learned behavior.<br> True<br> False
larisa [96]

Answer:

true

Explanation:

3 0
3 years ago
Read 2 more answers
Give a big-Oh characterization, in terms of n, of the running time of the Ex1-EX5 functions as shown in following Code Fragment
mash [69]

Answer:

Hello there, Please follow the step by step explanations for answer.

Explanation:

Hello there, Please follow the step by step explanations for answer.

Ex1 ( A):

it depends on n

=> O(n)

2.)

O(n/2) which is equal to O(n)

3.)O(n^2)

4.)O(2n) ==> O(n)

5.)O(n^3)

Also, see file attachment on this question for more clarity. Thanks and all the best.

8 0
3 years ago
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