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2 years ago

Which type of elevated stand does not need a tree?

Engineering

1 answer:

SashulF [63]2 years ago

4 0

Answer:

Elevated stands place the hunter above ground level. They can be tree stands placed in or against trees, or freestanding structures. They have become increasingly popular in recent years with both firearm and bow hunters.

Explanation:

You might be interested in

Does jupiter have a permanent storm thats looks like a large red spot?

alekssr [168]

Yes it does have a large spot

8 0

2 years ago

The undisturbed soil at given borrow pit is found to have the following property:

tankabanditka [31]

Answer:

Check the explanation

Explanation:

Determine the weight o ids in the each truck °slim the relation,

W,= $\frac{W}{1+w}$

Here, W is net weight of soil and water on the truck and w is water content

substitute 72 7 kN for W and 15% for w.

you will need to also determine the number of truck loads required using the relation:

Number of truck loads required = $\frac{W_{sc} }{W_{s}}$

Kindly check the attached image below for the full explanation to the question above.

7 0

2 years ago

As part of a heat treatment process, cylindrical, 304 stainless steel rods of 100-mm diameter are cooled from an initial tempera

saveliy_v [14]

Answer:

Explanation:

Given that:

diameter = 100 mm

initial temperature = 500 ° C

Conventional coefficient = 500 W/m^2 K

length = 1 m

We obtain the following data from the tables A-1;

For the stainless steel of the rod $\overline T = 548 \ K$

$\rho = 7900 \ kg/m^3$

$K = 19.0 \ W/mk \\ \\ C_p = 545 \ J/kg.K$

$\alpha = 4.40 \times 10^{-6} \ m^2/s \\ \\ B_i = \dfrac{h(\rho/4)}{K} \\ \\ =0.657$

Here, we can't apply the lumped capacitance method, since Bi > 0.1

$\theta_o = \dfrac{T_o-T_{\infty}}{T_i -T_\infty}} \\ \\ \theta_o = \dfrac{50-30}{500 -30}} \\ \\ \theta_o = 0.0426\\$

$0.0426 = c_1 \ exp (- E^2_1 F_o_)\\ \\ \\ 0.0426 = 1.1382 \ exp (-10.9287)^2 \ f_o \\ \\ = f_o = \dfrac{In(0.0374)}{0.863} \\ \\ f_o = 3.81$

$t_f = \dfrac{f_o r^2}{\alpha} \\ \\ t_f = \dfrac{3.81 \times (0.05)^2}{4.40 \times 10^{-6}} \\ \\ t_f= 2162.5 \\ \\ t_f = 36 mins$

However, on a single rod, the energy extracted is:

$\theta = pcv (T_i - T_{\infty} )(1 - \dfrac{2 \theta}{c} J_1 (\zeta) ) \\ \\ = 7900 \\times 546 \times 0.007854 \times (500 -300) (1 - \dfrac{2 \times 0.0426}{1.3643}) \\ \\ \theta = 1.54 \times 10^7 \ J$

Hence, for centerline temperature at 50 °C;

The surface temperature is:

$T(r_o,t) = T_{\infty} +(T_1 -T_{\infty}) \theta_o \ J_o(\zeta_1) \\ \\ = 30 + (500-30) \times 0.0426 \times 0.5386 \\ \\ \mathbf{T(r_o,t) = 41.69 ^0 \ C}$

5 0

2 years ago

Nowadays power supply on board ship is determine low and high voltage. From what range low & high voltage is being determine

zlopas [31]

Any Voltage used on board a ship if less than 1kV (1000 V) then it is called as LV (Low Voltage) system and any voltage above 1kV is termed as High Voltage. Typical Marine HV systems operate usually at 3.3kV or 6.6kV.

Explanation:

trust

6 0

1 year ago

The Machine Shop has received an order to turn three alloy steel cylinders. Starting diameter = 250 mm and length = 625 mm. Feed

Aneli [31]

Answer:

cutting speed is 365.71 m/min

Explanation:

given data

diameter D = 250 mm

length L = 625 mm

Feed f = 0.30 mm/rev

depth of cut = 2.5 mm

n = 0.25

C = 700

to find out

the cutting speed that will allow the tool life to be just equal to the cutting time for the three parts

solution

we will apply here cutting time formula that is express as

Tc = $\frac{\pi DL}{1000*f*V}$ .......................1

here D is diameter and L is length and f is feed and V is speed

so we get

Tc = $\frac{\pi (250)*625}{1000*0.3*V}$

Tc = $\frac{1636.25}{V}$

and we know tool life is

T = 3 × Tc ................................2

here T is tool life and Tc is cutting time

so find here tool life by put value in equation 2

T = 3 × $\frac{1636.25}{V}$

by taylor tool formula cutting speed is

$VT^{0.25} = 700$

V × $(3*\frac{1636.25}{V})^{0.25} = 700$

$V^{0.75}$ × 8.37 = 700

V = 365.71

so cutting speed is 365.71 m/min

5 0

2 years ago