PH+pOH=14
4.5+pOH=14
pOH=14-4.5
pOH = 9.5
We know that
[H⁺][OH⁻]=10⁻¹⁴,so
-log([H⁺][OH⁻])=-log10⁻¹⁴
-log [H⁺]+ (- log[OH⁻])= - log10⁻¹⁴,
- log[H⁺] = pH
- log[OH⁻] = pOH
- log10⁻¹⁴=-(-14)log10=14*1=14
pH + pOH =14
Answer:
CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH
Explanation:
CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH
More electronegative atom of halogen is , stronger acid will be.
First, balance the carbon and hydrogen atoms on both sides of the equation.Then, balance the oxygen atoms. ...Finally, balance anything that has become unbalanced.