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3 years ago

A5.0 kg TNT explosive, initially at rest, explodes into two pieces. One of the pieces weighing 2.0 kg flies off to

Physics

1 answer:

nordsb [41]3 years ago

4 0

Answer:

v = 24 m/s, rightwards

Explanation:

Given that,

The mass of TBT explosive = 5 kg

It explodes into two pieces.

One of the pieces weighing 2.0 kg flies off to the left at 36 m/s. Let left be negative and right be positive.

The law of conservation of momentum holds here. Let v be the final speed of the remaining piece. So,

$5\times 0=2\times (-36)+3\times v\\\\-72=-3v\\\\v=24\ m/s$

So, the final speed of the remaining piece is 24 m/s and it is in the right direction.

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How long will bus take to travel 150 km at an average speed of 40km/hr

romanna [79]

Answer:

3.75 hours

Explanation:

By $v = \frac{d}{t}$

where v is the velocity (or speed in this case)

d is the distance travelled

t is the time taken

$t = \frac{150}{40}=3.75$
Therefore it takes 3.75 hours for the bus to travel 150 km and 40 km/hr.

7 0

2 years ago

A football player kicks a football in a field goal attempt. When the football reaches its maximum height, what is the relationsh

Stels [109]

At position of maximum height we know that the vertical component of its velocity will become zero

so the object will have only horizontal component of velocity

so at that instant the motion of object is along x direction

while if we check the acceleration of object then it is due to gravity

so the acceleration of object is vertically downwards

so it is along y axis

so here these two physical quantities are perpendicular to each other

so correct answer would be

<em>C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other. </em>

3 0

3 years ago

Read 2 more answers

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stiv31 [10]

Explanation:

False

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3 0

3 years ago

3m/s for 12 seconds how dar would he walk

Sunny_sXe [5.5K]

I think 36m/12s because 3×12 =36

4 0

3 years ago

ou are out stargazing with your 13.4-cm telescope. You point your telescope at an interesting formation in the sky, which you th

Alinara [238K]

Answer:

θ = 4.716 10⁻⁶ rad

Explanation:

In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.

We use the diffraction equation for a slit

a sin θ = m λ

The minimum occurs at m = 1

sin θ = λ / a

Since the angles in these systems are very small, we can approximate the sine to its angle in radians

θ = λ / a

The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number

θ = 1.22 λ / a

Let's calculate

θ = 1.22 518 10⁻⁹ / 13.4 10⁻²

θ = 4.716 10⁻⁶ rad

8 0

3 years ago