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3 years ago

If urine has a density of 1.08 g/ml, what would be the mass of a 125 ml urine sample?

Chemistry

2 answers:

Ivahew [28]3 years ago

7 0

Answer:

135 g

Explanation:

the density (amount of mass in a given volume) formula is

$d=\frac{m}{v}$

$d= 1.08 g/mL\\v= 125 mL$

to know the amount of mass present in 125mL, we clear it from the formula

$d=\frac{m}{v}\\m=d.v$

$m=1.08\frac{g}{mL}. 125 mL\\ m=135 g$

Kay [80]3 years ago

6 0

Density=mass/volume
density=1.08
mass=?
volume=125ml
1.08=mass/125
mass=1.08x125
mass=1g

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3 years ago

When a student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter, the temperature of the resultant so

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Answer: 54.4 kJ/mol

Explanation:

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=1.0M\times 0.05=0.05mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=1.0\times 0.05L=0.05mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.05 mole of HCl neutralizes by 0.05 mole of NaOH

Thus, the number of neutralized moles = 0.05 mole

Now we have to calculate the mass of water:

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $50ml+50ml=100ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 100ml=100g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 100 g

$T_{final}$ = final temperature of water = $27.5^0C$

$T_{initial}$ = initial temperature of metal = $21.0^0C$

Now put all the given values in the above formula, we get:

$q=100g\times 4.18J/g^oC\times (27.5-21.0)^0C$

$q=2719.6J=2.72kJ$

Thus, the heat released during the neutralization = 2.72 KJ

Now we have to calculate the enthalpy of neutralization per mole of $HCl$ :

0.05 moles of $HCl$ releases heat = 2.72 KJ

1 mole of $HCl$ releases heat = $\frac{2.72}{0.05}\times 1=54.4KJ$

Thus the enthalpy change for the reaction in kJ per mol of HCl is 54.4 kJ

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How many formula units are there in 212 grams of mgCl2

AleksandrR [38]

Formula units are there in 212 grams of MgCl₂ are 830.56

Formula is the empirical of any ionic or covalent network solid compound used as an independent entity for stoichiometric calculations and it is the lowest whole number ratio of ions represented in an ionic compound

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MgCl₂ = 212 grams

1 mole of magnesium chloride has mass = 95.211 gram and contains 6.022×10²³formula units of magnesium chloride

Here 212 grams×6.022×10²³form unit of MgCl₂/95.211 gram = 830.56

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