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3 years ago

7

In a parallel circuit that has the same number and type of resistors as a series circuit the total resistance will be __________

and the total current will be ________. A.greater;greater B.lower;greater C.greater;the same D.the same;lower

2 answers:

cestrela7 [59]3 years ago

8 0

The answer is B:) hope that helps

zloy xaker [14]3 years ago

6 0

Answer:

B. lower, greater

...............

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4 years ago

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What do fossils provide evidence for?

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2 years ago

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Sally is trying to lift a heavy box, but is not strong enough to lift it. Would the force that she is applying to the box be an

mestny [16]

If you give it unbalanced force it would go up and if you can't give it enough it will stay a balanced force

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3 years ago

Calculate the wavelength and frequency at which the intensity of the radiation is a maximum for a blackbody at 298 K. You will n

Juliette [100K]

Answer:

Wavelength, $\lambda=9.72\times 10^{-6}\ m$

Frequency, $f=3.08\times 10^{13}\ Hz$

Explanation:

We need to find the intensity of the radiation is a maximum for a black body at 298 K. It can be calculated using Wein's displacement law. It is given by :

$\lambda T=2.898\times 10^{-3}\ m-K$

$\lambda=\dfrac{2.898\times 10^{-3}}{T}$

Here, T = 298 K

$\lambda=\dfrac{2.898\times 10^{-3}}{298}$

$\lambda=9.72\times 10^{-6}\ m$

If f is the frequency of black body radiation. It is given by :

$f=\dfrac{c}{\lambda}$

$f=\dfrac{3\times 10^8}{9.72\times 10^{-6}}$

$f=3.08\times 10^{13}\ Hz$

Hence, this is the required solution.

6 0

3 years ago

Two footballs (A & B) are thrown with the same amount of force. Football A has a greater mass. Describe the acceleration for

Sauron [17]

Newton's second law gives the relationship between force applied to an object, its mass and its acceleration:
$F=ma$
where F is the force, m the mass and a the acceleration.

A force F is applied to football A, whose mass is $m_A$ , and so the acceleration of this football will be given by (re-arranging the previous equation)
$a_A = \frac{F}{m_A}$

Similarly, the acceleration of football B will be
$a_B= \frac{F}{m_B}$
where $m_B$ is the mass of football B, and where the force F applied to the two footballs is the same.

Since football A has greater mass than football B, $m_A \ \textgreater \ m_B$ , if we compare the two previous formula we see that the acceleration of football B is greater than the acceleration of football A:
$a_B \ \textgreater \ a_A$
Therefore, if the same force is applied to the two footballs, football B will accelerate more than football A.

8 0

4 years ago