Answer: softer
The sound waves become weaker, so to an observer this wave is lighter sound.
Answer:
d = 4180.3m
wavelengt of sound is 0.251m
Explanation:
Given that
frequency of the sound is 5920 Hz
v=1485m/s
t=5.63s
let d represent distance from the vessel to the ocean bottom.
an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.


wavelengt of sound is
= v/f
= (1485)/(5920)
= 0.251 m
Answer:
Explanation:
Given
radius of circle=1.4 m
Height of stone above ground=1.5 m
Horizontal distance(R)=10 m
It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground

t=0.55 s
Initial horizontal velocity at the time of break is given by u


u=18.07 m/s
Therefore magnitude of centripetal acceleration is given by

K=1400*V^2/2
K=20000*25^2/2. => 1400*V^2/2=20000*25^2/2 <=> 1400*V^2=20000*25^2
14*V^2=200*225
v^2=100*225/7
v=250/7^(1/2)
Answer: 250*7^(1/2)/7