Answer:
v = 4.67 m
Explanation:
It is given that,
Height of the object is 24.8 cm
Height of the formed image is -3.09 cm
Object distance is 37.5 cm, it is negative always
We need to find the image distance. Let v is the image distance. Magnification of an object is given by the formula as follows :
So, the image is formed at a distance of 4.67 m.
Sally's displacement (5m forward) is 10m less than her distance traveled (15m). <em>(B)</em>
We can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is moving.
<h3>What are the utricle and saccule?</h3>
These are small organs located in the inner ear. They serve a very important function in our everyday life. These otolith organs are responsible for the detection of movement and provide us with a sense of spatial orientation. They accomplish this by stimulating very small, hair-like cells with a specialized fluid.
Therefore, we can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is accelerating or decelerating.
To learn more about the inner ear visit:
brainly.com/question/3535321?referrer=searchResults
use the formula: v^2=(3kT)/m
Where:
<em>v is the velocity of a molecule</em>
<em>k is the Boltzmann constant (1.38064852e-23 J/K)</em>
<em>T is the temperature of the molecule in the air</em>
<em>m is the mass of the molecule</em>
For an H2 molecule at 20.0°C (293 K):
v^2 = 3 × 1.38e-23 J/K × 293 K / (2.00 u × 1.66e-27 kg/u)
v^2 = 3.65e+6 m^2/s^2
v = 1.91e+3 m/s
For an O2 molecule at same temp.:
v^2 = 3 × 1.38e-23 J/K × 293 K / (32.00 u × 1.66e-27 kg/u)
v^2 = 2.28e+5 m^2/s^2
v = 478 m/s
Therefore, the ratio of H2:O2 velocities is:
1.91e+3 / 478 = 4.00
