Question

A skateboarder starts up a 1.0-m-high, 30° ramp at a speed of 7.6 m/s . The skateboard wheels roll without friction. At the top, she leaves the ramp and sails through the air. How far from the end of the ramp does the skateboarder touch down?

Answer 1

Answer:

t = 1.084 s

s = 8.25 m

Explanation:

given,

height from where skate board start (h) = 1 m

speed = 7.6 m/s

we know

v² = u² + 2 g h                      

v² =7.6² + 2×9.81× 1

v = 8.79 m/s                        

$v_y = v sin \theta$

$v_y =8.79\times sin 30^0$

$v_y = 4.39 m/s$

$s = s_o + v_y \times t +\dfrac{1}{2}at^2$

$0 = 1 + 4.39 \times t - 4.9 t^2$

t = 1.084 s

then horizontal distance

$s =v_x \times t$

$s = 8.79 \times cos 30^0 \times 1.084$

s = 8.25 m