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3 years ago

Triton is a moon of Neptune. It has a

Physics

1 answer:

Mnenie [13.5K]3 years ago

6 0

Answer:

Well, Your answer will be is 840.96 mi. 

Good Luck!

$^{Itsbrazts}$

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What color do you think an object would be if it reflected all colors of the visible spectrum?

Lubov Fominskaja [6]

C) The object would be WHITE.

We call "white light" to the sunlight, but referred to the visible part of spectrum. If the object reflects all the light, it appears as a white object.

7 0

3 years ago

In hooke's law is force directly proportional to extension?

gavmur [86]

Answer:

Explanation:

Hooke's Law is a principle of physics that states that the that the force needed to extend or compress a spring by some distance is proportional to that distance. ... In addition to governing the behavior of springs, Hooke's Law also applies in many other situations where an elastic body is deformed

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3 years ago

g A proton moves at 3.60 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.

Ivanshal [37]

Explanation:

It is given that,

Speed of the proton, $v=3.6\times 10^5\ m/s$

Electric field, $E=9.4\times 10^3\ N/C$

(a) Distance covered, d = 4 cm = 0.04 m

Let t is the time interval required for the proton to travel 4.00 cm horizontally. It can be calculated as :

$t=\dfrac{d}{v}$

$t=\dfrac{0.04}{3.6\times 10^5}$

$t=1.11\times 10^{-7}\ s$

t = 111 ns

(b) Since, initial speed = 0 in vertical direction. So,

So, q E = ma

$a_y=\dfrac{E_yq}{m}$

Displacement is given by :

$y=ut+\dfrac{1}{2}a_yt^2$

$y=\dfrac{1}{2}\dfrac{E_yq}{m}t^2$

$y=\dfrac{1}{2}\times \dfrac{9.4\times 10^3\times 1.67\times 10^{-19}}{1.67\times 10^{-27}}(1.11\times 10^{-7})^2$

$y=0.00579\ m$

(c) For vertical component of velocity, use equation of kinematics as :

$v_y^2-u^2=2a_yd$ (d = 4 cm)

$v=\sqrt{2\dfrac{E_yq}{m}d_y}$

$v=\sqrt{2\times \dfrac{9.4\times 10^3\times 1.67\times 10^{-19}}{1.67\times 10^{-27}}\times 0.04}$

$v=2.74\times 10^5\ m/s$

For horizontal component of velocity,

$v_x=\dfrac{d}{t}$

$v_x=\dfrac{0.04}{1.11\times 10^{-7}}$

$v_x=3.6\times 10^5\ m/s$

Hence, this is the required solution.

3 0

3 years ago

A satellite of mass 1.02 metric tons orbits Earth at a constant height. If the mass of Earth is 6 x 10^24 kg,its radius is 6,360

xz_007 [3.2K]

Answer:

height = 1.5 x 10⁶ m = 1500 km

Explanation:

We can use the formula of gravitational force from the Newton's Gravitational Law:

$F = \frac{Gm_{1}m_{2}}{r^2}$

where,

F = Gravitational Force = 6.6 x 10³ N

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of earth = 6 x 10²⁴ kg

m₂ = mass of satellite = (1.02 tons)(1000 kg/1 ton) = 1.02 x 10³ kg

r = distance between center of earth and satellite = ?

Therefore, using these values in the equation, we get:

$6.6\ x\ 10^3\ N = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{r^2}\\\\r^2 = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{6.6\ x\ 10^3\ N}\\\\$