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solniwko [45]
3 years ago
10

Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone

Chemistry
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

butyne

Explanation:

alkane, alkene, and alkyne are all examples of hydrocarbons.

butyne = alkyne

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Can someone help please I will give Brainlyiest
kotykmax [81]

Answer:

See Explanation

Explanation:

moles of NH₃ = 11.9g/17.03 g/mol = 0.699 mole

moles of CN₂OH₄ = 1/2(0.699) mole =0.349 mole

Theoretical yield of CN₂OH₄ = (0.349 mole)(60 g/mole) = 20.963 grams

%Yield = Actual Yield/Theoretical Yield x 100%

= 18.5g/20.963g x 100% = 88.25%

7 0
3 years ago
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Ryan and Abigail are conducting an experiment. They place six ice cubes into a beaker and find the combined mass. They allow the
JulijaS [17]

The mass of the ice cubes and the water will be equal because the same amount of matter is in the beaker.

Matter is anything that has mass and occupy space. All substances are composed of matter. According to the law of conservation of mass, matter can neither be created nor destroyed but can be converted from one form to another.

Since mass is the quantity of matter in a substance, the mass of the ice cubes and the water will be equal because the same amount of matter is in the beaker.

Learn more: brainly.com/question/25150590

4 0
2 years ago
What are the names of the components (each shown with a leader and a line) of a circuit shown in the diagram? Please help!!!!
alekssr [168]
Maybe: Battery, wire, lamp and switch
6 0
3 years ago
A solution is made by dissolving 0.656 mol of nonelectrolyte solute in 869 g of benzene. calculate the freezing point, tf, and b
solmaris [256]
Answer is: the freezing point is 1.63°C and boiling point is 82.01°C.<span>.

1) n(</span><span>nonelectrolyte solute) = 0.656 mol.
</span>m(C₆H₆ - benzene) = 869 g ÷ 1000 g/kg.
m(C₆H₆) = 0.869 kg.<span>
b(solution) = n(</span>nonelectrolyte solute) ÷ m(C₆H₆).<span>
b(solution) = 0.656 mol ÷ 0.869 kg.
b(solution) = 0.754 mol/kg.

2) ΔT = Kf(benzene) · b(solution).
ΔT = 5.12°C/m · 0.754 m.
ΔT = 3.865°C.
Tf = 5.50°C - 3.865°C.
Tf = 1.63°C.
</span>
3) ΔTb = Kb(benzene) · b(solution).
ΔTb = 2.53°C/m · 0.754 m.
ΔTb = 1.91°C.
Tb = 80.1°C + 1.91°C.
Tb = 82.01°C.<span>

</span>
4 0
3 years ago
100 POINTS!!!
Paul [167]

what do u need help with u pls respond quickly

6 0
2 years ago
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