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Ede4ka [16]
3 years ago
5

Pls help Plot the point (5,9)

Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
6 0
Go five across the x axis, then go nine straight up from there
elena-s [515]3 years ago
4 0
All u do is go to 5 and up nine and just put a little cross
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List four things that could happen to water used in watering a local golf course
spin [16.1K]

Explanation:

feed the grass

evaporate

reclaimed

fall in the sand( bunkers under ground)

if this does not help, please be more specific

3 0
3 years ago
Write the name of the following compound: H3PO4
bixtya [17]
Phosphoric acid<span>, also known as orthophosphoric acid or phosphoric(V) acid, is a mineral acid with the chemical formula </span><span>H3PO4</span>
7 0
3 years ago
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What is the maximum mass of b4c that can be formed from 2.00 moles of boron(iii) oxide?
anzhelika [568]

The maximum mass of B₄C that can be formed from 2.00 moles of boron (III) oxide is 55.25 grams.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the relative amount of moles of reactants and products present in the given chemical reaction.

Given chemical reaction is:

2B₂O₃ + 7C → B₄C + 6CO

From the stoichiometry of the reaction, it is clear that:

2 moles of B₂O₃ = produces 1 mole of B₄C

Now mass of B₄C will be calculated by using the below equation:

W = (n)(M), where

  • n = moles = 1 mole
  • M = molar mass = 55.25 g/mole

W = (1)(55.25) = 55.25 g

Hence required mass of B₄C is 55.25 grams.

To know more about stoichiometry, visit the below link:

brainly.com/question/25829169

#SPJ1

3 0
2 years ago
Looking at page 14 of the earth science tables, how does the temperature change as a balloon rises through the Troposphere Strat
givi [52]

Answer:

Decreases

Explanation:

The temperature decreases when latitude increases.

5 0
3 years ago
Exactly 5000 mL of air at 223K is warmed and has a new volume of 8.36 liters. What is the new temperature?
34kurt

Answer:

The new temperature is 373 K

Explanation:

Step 1: Data given

Volume air = 5000 mL = 5.0 L

Temperature = 223K

New volume = 8.36 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒V1 = the initial volume = 5.0 L

⇒T1 = the initial temperature = 223 K

⇒V2 = the new volume = 8.36 L

⇒T2 = the new temperature

5.0/223 = 8.36 /T2

T2 = 373 K

The new temperature is 373 K

7 0
3 years ago
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