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jasenka [17]
3 years ago
7

The mass of single iridium atom is 3.19*10^-22 grams how many iridium atoms would be in 56.4 milligrams of iridium

Chemistry
2 answers:
g100num [7]3 years ago
8 0

Answer:162626363637272772.8766

Explanation:

13322/726513/272727-277373

earnstyle [38]3 years ago
3 0
First convert milligrams to grams by dividing it by 1000. This gets us 0.0564 grams of iridium. Since we know the ratio between one iridium atom and grams is 1 atom/3.19*10^22 grams, use that ratio as the conversion factor in dimensional analysis. 0.0564 grams * (1 atom/3.19*10^22 grams). Grams cancel out and we are left with 1.77*10^20 atoms.
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4) Titration

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What is the tool used for measuring volume?
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Number of grams of hydrogen than can be prepared from 6.80g of aluminum​
Anastaziya [24]

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0.7561 g.

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<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>

It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.

  • Firstly, we need to calculate the no. of moles of (6.8 g) of Al:

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0.252 mol of Al need to react → ??? mol of H₂.

∴ the no. of moles of H₂ that can be prepared from 6.80 g of aluminum = (3.0 mol)(0.252 mol)/(2.0 mol) = 0.3781 mol.

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