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jasenka [17]
2 years ago
7

The mass of single iridium atom is 3.19*10^-22 grams how many iridium atoms would be in 56.4 milligrams of iridium

Chemistry
2 answers:
g100num [7]2 years ago
8 0

Answer:162626363637272772.8766

Explanation:

13322/726513/272727-277373

earnstyle [38]2 years ago
3 0
First convert milligrams to grams by dividing it by 1000. This gets us 0.0564 grams of iridium. Since we know the ratio between one iridium atom and grams is 1 atom/3.19*10^22 grams, use that ratio as the conversion factor in dimensional analysis. 0.0564 grams * (1 atom/3.19*10^22 grams). Grams cancel out and we are left with 1.77*10^20 atoms.
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What direction do the plates have to move in order for an earthquake to occur?
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PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

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3 years ago
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2. What group is Ballardium located? (Bu) *
elena-14-01-66 [18.8K]

Answer:

This question appears incomplete

Explanation:

There is no such element known as "Ballardium (Bu)" in the periodic table. However, there are elements with a bit of similarity in spellings and pronunciation such as Beryllium (Be) which is found in group 2 (meaning it is an alkali earth metal), Berkelium (Bk) which is an actinide (meaning it is radioactive) and Vanadium (V) which is found in group 5 of the periodic table (meaning it's a transition metal).

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vladimir2022 [97]

Answer:

B- Sodium loses an electron.

D- Fluorine gains an electron.

Sodium is oxidized.

Explanation:

The reaction equation is given as:

        Na  + F →  NaF

In this reaction, Na is the reducing agent. It loses an electron and then becomes oxidized. By so doing, Na becomes isoelectronic with Neon.

Fluorine gains the electron and then becomes reduced. This makes fluorine also isoelectronic with Neon.

This separation of charges on the two species leads to an electrostatic attraction which forms the ionic bonds.

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