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coldgirl [10]
3 years ago
14

C. How is EM created?

Chemistry
2 answers:
diamong [38]3 years ago
7 0
Electromagnetic waves are formed when an electric couples with a magnetic field Magnetic and electric fields of an electromagnetic wave are perpendicular to each other and to the direction of the wave.
Arada [10]3 years ago
6 0
EM is created by moving charges back and forth will produce oscillating electric and magnetic fields, and these travel at the speed of light
You might be interested in
A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0
3 years ago
Calculate the mass of carbon dioxide released when 185.000 g of copper carbonate [molar mass = 123.5 g/mol] is heated (assuming
Vinvika [58]

Answer:

The answer to your question is: 65.9 g released of CO2

Explanation:

MW CO2 = 44 g

MW CuCO3 = 123.5 g

CO2 released = ?

CuCO3 = 185 g

                            CuCO3     ⇒    CO2   +    CuO

                             123.5  -----------  44g

                             185 g -----------    x

                           x = (185 x 44) / 123.5

                           x = 65.9 g released of CO2

8 0
2 years ago
Where is the earth curst thinkest
Dafna11 [192]
The crust of the Earth is thickest beneath the continents. 
6 0
2 years ago
I need help!! ASAP please..
Marrrta [24]

Answer:

164 g

Explanation:

8 0
2 years ago
A student has 100. mL of 0.400 M CuSO4 (aq) and is asked to make 100. mL of 0.150 M CuSO4 (aq) for a spectrophotometry experimen
GenaCL600 [577]

Answer:

We have to take 37.5 mL of a 0.400 M solution

Explanation:

Step 1: Data given

Stock volume = 100 mL  = 0.100L

Stock concentration 0.400 M

Volume of solution he wants to make = 100 mL = 0.100L

Concentration of solution he wants to make = 0.150 M

Step 2: Calculate the volume of 0.400 M CuSO4 needed

C1*V1 = C2*V2

⇒with C1 = the stock concentration = 0.400M

⇒with V1 = the volume of the stock = TO BE DETERMINED

⇒with C2 = the concentration of the solution he wants to make = 0.150 M

⇒with V2 = the volume of the solution made = 0.100 L

0.400 M * V1 = 0.150M * 0.100L

V1 = (0.150M*0.100L) / 0.400 M

V1 = 0.0375 L = 37.5 mL

We have to take 37.5 mL of a 0.400 M solution

5 0
3 years ago
Read 2 more answers
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